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LUCKY_DIMON [66]
3 years ago
15

When solving the equation -3a^2=7a-3 using the quadratic formula, what values should be used for a, b, c

Mathematics
1 answer:
Leni [432]3 years ago
6 0
You configure the formula first to equal it to 0. Also in the order of from high powered x to lower powered and constant.

-3a^2 - 7a + 3 = 0

In order now. A is first one B is second one and C is third one.

Answer is 4
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Answer:

The value of the given expression when z=27 is 16

Therefore \frac{7}{9}(z-18)+\frac{1}{3}z=16 when z=27

Step-by-step explanation:

Given expression is \frac{7}{9}(z-18)+\frac{1}{3}z

To find the value of the expression when z=27 :

First simplify the given expression

\frac{7}{9}(z-18)+\frac{1}{3}z

=\frac{7(z-18)}{9}+\frac{1}{3}z

=\frac{7z-126}{9}+\frac{1}{3}z

=\frac{7z-126+3z}{9}

=\frac{7z-126+3z}{9}

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Put z=27 in the above equation we get

=\frac{10(27)-126}{9}

=\frac{270-126}{9}

=\frac{144}{9}

=\frac{144}{9}

=16

\frac{7}{9}(z-18)+\frac{1}{3}z=16

Therefore the value of the given expression when z=27 is 16

Therefore \frac{7}{9}(z-18)+\frac{1}{3}z=16 when z=27

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Answer:

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