When shopping for life insurance, the best strategy is to:

Mathematics

2 answers:

I am Lyosha [343]2 years ago

8 0

Answer:

C. Figure out how much you need, then comparison shop using the Web and other resources.

Step-by-step explanation:

choli [55]2 years ago

6 0

Answer:

answer is "C"

Step-by-step explanation:

just took the test on edge 2020

You might be interested in

Consider the following pair of equations: −x − y = −5 y = x + 1 If the two equations are graphed, at what point do the lines rep

Mnenie [13.5K]

-x - y = -5
y = x + 1

-x -(x + 1) = -5
-x - x - 1 = -5
-2x = -5 + 1
-2x = -4
x = -4/-2
x = 2

y = x + 1
y = 2 + 1
y = 3

solution is : (2,3)

6 0

3 years ago

Use mulipation to find 2 equivalent fractions

laila [671]

1/2 is equivalent to 2/4 because,

2(1/2) = 2/4

So as you can see if you multiply the numerator(top) and the denominator(bottom) by the same number, you get an equivalent fraction! In my example you can see that I multiplied both by 2.

5 0

3 years ago

Can someone help please

myrzilka [38]

<h3>Answer: 15x^(7/3) - 8x^(7/4) + x + 9000</h3>

=========================================================

Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

Marginal cost = derivative of cost function

Marginal cost = C ' (x)

Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.

$\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\$

$C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\$

D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).

To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.

Therefore, we go from this

$C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\$