On 1, I need help, and for 2, is the answer right?

A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish

Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or $\frac{x}{y}=\frac{333}{444}$

⇒ $\frac{x}{y}=\frac{3}{4}$

⇒ y = $\frac{4x}{3}$ --------(1)

Similarly x' : y' = 333 : 444

⇒ $\frac{x'}{y'}=\frac{333}{444}$

⇒ $\frac{x'}{y'}=\frac{3}{4}$

⇒ x' = $\frac{3y'}{4}$ ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

$\frac{x+y}{x'+y'}=\frac{464646}{555}$

Now we replace the values of x and y' from equation (1) and equation (2)

$\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}$

$\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}$

$\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}$

$\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}$

$\frac{x}{y'}=\frac{232323}{370}$

$\frac{y'}{x}=\frac{370}{232323}$

$\frac{y'}{x}=\frac{10}{6279}$

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0

3 years ago

A church group ordered a total of 22

blagie [28]

Answer:

the group bought 10 burger and 12 drinks

Step-by-step explanation:

6.25×10=62.5

92.50-62.5=30

30÷2.50=12

3 0

3 years ago

BCDE is a parallelogram. What is the measure of ∠BEC? Enter your answer in the box. ° A parallelogram B C D E. Side E D is the b

Elenna [48]

Solution:

In Parallelogram B CDE

BC= DE, BC ║DE

CD = BE , CD ║BE

Also, ∠B=∠D and ∠C=∠E →→In a parallelogram opposite sides are equal and parallel, as well as opposite angles are equal.Diagonals Bisect each other.

∠B= 60° , ∠C ED= 40°

CE is a transversal and BC║DE.

∠CED=∠BCE = 40° →→Alternate interior angles

In Δ BCE

∠B + ∠BCE + ∠BEC= 180°→→→Angle sum property of Triangle.

60° + 40° + ∠ B E C= 180°

100° + ∠BEC=180°

∠BEC= 180° -100°

∠BEC= 80°

3 0

3 years ago

Solve [y] = -18. Help pls

777dan777 [17]

Answer:

[y]=-18 so y belongs to (-18,-17)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If x+ay =b and ax-by=c Then find out x , y . (with process)

n200080 [17]

Answer:

The solution of the given system of equations is,

$x=\frac{b^2+ac}{a^2+b};\; y=\frac{ab-c}{a^2+b}$

Step-by-step explanation:

The given equations are :

x + ay = b .......(1)

ax - by = c .......(2)

We will use 'Substitution Method' to solve the given system of equations.

In this method, we will find out the value of either of the two variables that is 'x' and 'y' from one of the two equations in terms of the another variable and then substitute that value in the other equation to find the value of the another variable.

Now, we will be finding out the value of 'x' in terms of 'y' from equation (1) and then substitute it in the equation (2).

Consider the equation (1), that is,

x + ay = b ⇒ x = b - ay ........(3)

Substitute the value of 'x' from (3) in (2), we get

a(b - ay) - by = c

⇒ab - a²y - by = c

⇒-a²y - by = c - ab

⇒-y(a²+b) = c - ab

⇒y(a²+b) = ab - c

$\implies y=\frac{ab-c}{a^{2}+b}$