Assuming the cylinder is closed at both ends
Surface area = 2 pi r^2 + 2 pi r h = 108
now h = r/2 so we have:-
2pi r^2 + pi r^2= 108
3 pi r^2 = 108
r^2 = 11.459
r = 3.385
so the height h = 1.693 m to nearest thousandth
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>
You have to show a picture so we can solve this problem you’re having.
Answer: 3.61km or √13
Step-by-step explanation:
Given Data:
Sides of hexagon = 2km each
Distance walked by Ama = 5km
Therefore;
Let Ama starting position be the origin.
With this She would travel along two edges and then go halfway along a third.
Her new x- coordinate would be
= 1 + 2 + 1/2 = 7/2
Because she travels a distance of 5km which translates to 2 and half side of the Hexagon
= 2*1/2
= 1km. On her x-coordinates
For her y-coordinate we use same principles as x-coordinates
= √3 + 0 - √3/2
= √3/2
Therefore her distance walked
= √ ( (7/2)^2 + (√ 3/2)^2 )
= √ ( 49/4 + 3/4 )
= √ 13
= 3.61km
The problem in the picture would be
x^2+10x+21
