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Vikki [24]
2 years ago
8

Luke’s has seven coins. He can make 11p with two of his coins. He can make 11p with three of his coins. He can make 11p with fou

r of his coins. What are the seven coin that Luke’s has?
Mathematics
1 answer:
Svet_ta [14]2 years ago
7 0

Answer:

1p 2p 2p 2p 5p 5p 10p

Step-by-step explanation:

Available coins that are less than 11p:  1p 2p 5p 10p

11p with two coins ⇒ 1p + 10p only

11p with three coins ⇒ 1p + 5p + 5p only

11p with three coins ⇒ 2p + 2p + 2p + 5p only

Therefore, the seven coins that Luke has are:

1p 2p 2p 2p 5p 5p 10p

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What is the range of the following data values? 48,61,57,82,79
jenyasd209 [6]

Answer:

Answer is 34

Step-by-step explanation:

Ordering the numbers from least to greatest, we get:

48, 57, 61, 79, 82

highest - lowest = 82-48

82-48=34

the range is 34

6 0
3 years ago
Read 2 more answers
peter ​says, "If you subtract 11 from my number and multiply the difference by -2​, the result is -26." What is Peter's number?
8_murik_8 [283]

Answer:

24

Step-by-step explanation:

Reverse

-26/-2= 13

13+11=24

Check

24-11=13

13×-2= -26

4 0
4 years ago
Read 2 more answers
(-7x + 6) - (-2x + 9x - 2)
elena-s [515]

Answer:

-14x+4

Step-by-step explanation:

So the first set of paranthese don't really matter so you can rewrite it to this

-7+6-(-2x+9x-2)

Then  infront of the ( there is a - which means a -1. Now just do the disbutive property.

-7x+6+2x-9x+2

Now add like terms and you get your finial answer!

-14x+4

3 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?
ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0
3 years ago
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Marysya12 [62]
Vertical line is x=0
8 0
3 years ago
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