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3 years ago

Identify each matrix A such that A^2 has identical diagonal elements?

Mathematics

1 answer:

Maksim231197 [3]3 years ago

6 0

Answer:

The correct matrices are:

Matrix:

7 1 5

1 5 7

5 7 1

all diagonal elements of A^2 are: 7^2 + 1^2 + 5^2

Matrix:

9 18 27

27 -9 18

18 27 9

all diagonal elements of A^2 are: 9^2 + 27*18 + 18*27 or (-9)^2

Matrix:

8 1 6

6 8 1

1 6 8

all diagonal elements of A^2 are: 8^2 + 6*1 + 1*6

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Zolol [24]

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2 years ago

Fill in the missing value to make the equations true.

Furkat [3]

Answer:

a) 7/4 b) 5 c) 2

Step-by-step explanation:

Logrithmic Rule for a and b

Let a, M, N be positive real numbers.

logaM - logaN = loga(M/N)

log9(7) - log9(4) = log9 (7/4)

logaM + logaN = logaMN

log2 (x) + log2(9) = log2(45)

x9=45

(x9)/9 = 45/9

x = 5

Change of base formula.

logb(x)=logd(b)/logd(x)

x log6(5) = log6(25) divide each term by log6(5)

x log6(5) / log6(5) = log6(25) / log6(5) Cancel common factor log6(5)

x = log6(25) / log6(5)

x = log6(5^2) / log6(5)

Expand log6(5^2) by moving 2 outside the logarithm.

x = 2log6(5) / log6(5) cancel the like term log6(5)

x = 2

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3 years ago

The mapping below represents all of the points on the graph of functionf.

Rom4ik [11]

Answer:

$\{-4, -1, 0, 2, 7\}$

Step-by-step explanation:

The domain of the function is the set of all possible inputs for the function. Therefore, the set of all possible inputs is $\{-4, -1, 0, 2, 7\}$ .

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

A new medical test provides a false positive result for hepatitis 2% of the time that is a perfectly healthy subject being teste

Oxana [17]

Given that X be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.

The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02

Part A:

The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:

 $P(X)={ ^nC_xp^x(1-p)^{n-x}} \\ \\ P(0)={ ^{30}C_0(0.02)^0(1-0.02)^{30-0}} \\ \\ =1(1)(0.98)^{30}=0.5455$


Part B:

The mean of a binomial distribution is given by

 $\mu=np \\ \\ =30(0.02) \\ \\ =0.6$

The standard deviation is given by:

 $\sigma=\sqrt{np(1-p)} \\ \\ =\sqrt{30(0.02)(1-0.02)} \\ \\ =\sqrt{30(0.02)(0.98)}=\sqrt{0.588} \\ \\ =0.7668$


Part C:

This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.

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3 years ago