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pishuonlain [190]
3 years ago
14

you took a 20 question test and received a 65% on the test. how many question did you answer correctly

Mathematics
1 answer:
sukhopar [10]3 years ago
8 0
You answered 13 correct, you can search this up by putting 65 percent of 20 and you would get the answer, just in case you have other questions like this!
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A deck of cards with four suits; hearts, diamonds, spades, and clubs. you pick one card, put it back and thennpick another card.
Llana [10]

1. First, let us find the probability that the first card is a diamond.

Now, since we are given that there are four suits and there are, assumably, an equal number of cards in each suit, we can say that the probability of choosing a diamond card is 1/4. We can also write this out as such, where D = Diamond:

Pr(D) = no. of diamond cards / total number of cards

There are 52 cards in a deck, and 13 cards of each suit, thus:

Pr(D) = 13/52 = 1/4

2. Now we need to calculate the probability of not choosing a diamond as the second card.

In many cases, when given a problem that requires you to find the probability of something not happening, it may be easier to set it out as such:

Pr(A') = 1 - Pr(A)

ie. Pr(A not happening, or not A) = 1 - Pr(A happening, or A)

This works because the total probability is always 1 (100%), and it makes sense that to find the probability of A not happening, we take the total probability and subtract the probability of A actually happening.

Thus, given that we have already calculated that the probability of choosing a Diamond is 1/4, we can now set this out as such:

Pr(D') = 1 - Pr(D)

Pr(D') = 1 - 1/4

Pr(D') = 3/4

3. Now we come to the final step. To find the probability of something and then something else happening, we must multiply the two probabilities together. Thus, given that Pr(D) = 1/4 and Pr(D') = 3/4, we get:

Pr(D)*Pr(D') = (1/4)*(3/4)

= 3/16

Thus, the probability of choosing a diamond as the first card and then not choosing a diamond as the second card is 3/16.

7 0
3 years ago
Does Y equals 3X minus to have a solution
Tcecarenko [31]

Answer:

Graph the second equation by finding two data points. By setting first x and then y equal to zero it is possible to find the y intercept on the vertical axis and the x intercept on the horizontal axis. At the point of intersection of the two equations x and y have the same values.

5 0
3 years ago
Read 2 more answers
Help me answer this please:)
Dmitrij [34]

Answer:

A and B

Step-by-step explanation:

\frac{7x+6}{2}\leq 3x+2 < ==multiply\ both\ sides\ by\ 2\\2(\frac{7x+6}{2}\leq 3x+2)\\\\7x+6\leq6x+4 < ==subtract\ -6x\ from\ both\ sides\ \\-6x \ \ -6x\\\\x+6\leq4 < ==subtract\ 6\ from\ both\ sides\\-6 \ \ \ -6\\\\x\leq-2 < ==answer\ should\ be\ anything\ less\ than\ or\ equal\ to\ -2

Now, look at your answer choices, which options are less than or equal to -2?

x ≤ -2, Check your answers:

A. -3 ≤ -2?

This statement is correct (-3 is < -2)

B. -2 ≤ -2 <== our original answer

This statement is correct (-2 is = to -2)

C. -1 ≤ -2

This statement is incorrect (-1 is > -2, not ≤ -2)

D. 0 ≤ -2

This statement is incorrect (0 is > -2, not ≤ -2)

E. 1 < -2

This statement is incorrect (1 is > -2, not ≤ -2)

Therefore, the correct options are A and B

Hope this helps!

6 0
2 years ago
q(x)= x 2 −6x+9 x 2 −8x+15 ​ q, left parenthesis, x, right parenthesis, equals, start fraction, x, squared, minus, 8, x, plus, 1
AURORKA [14]

According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.

<h3>What is the behavior of a functions close to one its vertical asymptotes?</h3>

Herein we know that the <em>rational</em> function is q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15), there are <em>vertical</em> asymptotes for values of x such that the denominator becomes zero. First, we factor both numerator and denominator of the equation to see <em>evitable</em> and <em>non-evitable</em> discontinuities:

q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15)

q(x) = [(x - 3)²] / [(x - 3) · (x - 5)]

q(x) = (x - 3) / (x - 5)

There are one <em>evitable</em> discontinuity and one <em>non-evitable</em> discontinuity. According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.

To learn more on rational functions: brainly.com/question/27914791

#SPJ1

8 0
1 year ago
Ivanna is playing a game in which she spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a num
saul85 [17]

Answer:

The spinner has 6 equal-sized slices, so each slice has a 1/6 probability of showing up.

I guess that we want to find the expected value in one spin:

number 1: wins $1

number 2: wins $3

number 3: wins $5

number 4: wins $7

number 5: losses $8

number 6: loses $8

The expected value can be calculated as:

Ev = ∑xₙpₙ

where xₙ is the event and pₙ is the probability.

We know that the probability for all the events is 1/6, so we have:

Ev = ($1 + $3 + $5 + $7 - $8 - $8)*(1/6) = $0

So the expected value of this game is $0, wich implies that is a fair game.

8 0
3 years ago
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