Question

On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population increases by a factor of 555 every 222222 days, and can be modeled by a function, LLL, which depends on the amount of time, ttt (in days). Before the first day of spring, there were 760076007600 locusts in the population. Write a function that models the locust population ttt days since the first day of spring.

Answer 1

Answer:

          $L(t)=7600(5)^{t/2}$

Explanation:

Amend the typos for better understanding:

• On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population increases by a factor of 5 every 2 days, and can be modeled by a function, L, which depends on the amount of time, t (in days). Before the first day of spring, there were 7600 locusts in the population. Write a function that models the locust population t days since the first day of spring.

Solution

A function that grows with a constant factor is modeled by an exponential function of the kind:

                                      $F(x)=A\cdot (B)^x$

Where A is the initial value, B is the constant growing factor, and x is the number of times the growing factor applies.

Since the population increases by a factor of 5 every 2 days, the power x of the exponential function is t/2, and the factor B is 5.

The initial popultaion A is 7600.

Thus, the function that models the locust population t days since the first day of spring is:

             $L(t)=7600(5)^{t/2}$