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yan [13]
2 years ago
15

During an election year, why would a senator want to determine a mode?

Mathematics
2 answers:
Brilliant_brown [7]2 years ago
4 0

Answer:

to determine which issue is most important to the general public

Step-by-step explanation:

got it right edge 2021

pickupchik [31]2 years ago
3 0

Answer:

Step-by-step explanation:

During an election year, why would a senator want to determine a mode?

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3/7 to fill a large glass. How many glasses can be filled using 50 cartons of milk
NeTakaya
50 / (3/7) =
50 * 7/3 =
350/3 =
116.66....so it would fill 116 glasses


6 0
3 years ago
tina bought some nail polish and lip gloss at the store. the nail polish cost $4.50 per bottle and lip gloss cost $7 per tube. t
viktelen [127]
5 nail polish and 4 lip gloss

5 x 4.5 =22.5
4 x 7    =28
28+22.5=50.50
5 0
3 years ago
Write the first four terms in the multiplication pattern given by the formula:<br><br>10 · 5n
yanalaym [24]
We have that
an=<span>10 * 5n---------------> an=50*n

then

for n=1
a1=50*1=50

</span>for n=2
a2=50*2=100

for n=3
a3=50*3=150

for n=4
a4=50*4=200<span>


the answer is
</span><span>the first four terms are [50,100,150,200]</span><span>



</span>
7 0
3 years ago
In a certain Algebra 2 class of 29 students, 7 of them play basketball and 24 of them play baseball. There are 3 students who pl
antiseptic1488 [7]

Answer:

\frac{5}{29}

Step-by-step explanation:

Let n(A) represent students playing basketball, n(B) represent students playing baseball.

Then, n(A)=7, n(B)=24

Let n(S) be the total number of students. So, n(S)=29.

Now,

P(A)=\frac{n(A)}{n(S)}=\frac{7}{29}

P(B)=\frac{n(B)}{n(S)}=\frac{24}{29}

3 students play neither of the sport. So, students playing either of the two sports is given as:

n(A\cup B)=n(S)-3\\n(A\cup B)=29-3=26

∴ P(A\cup B)=\frac{n(A\cup B)}{n(S)}=\frac{26}{29}

From the probability addition theorem,

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Where, P(A\cap B) is the probability that a student chosen randomly from the class plays both basketball and baseball.

Plug in all the values and solve for P(A\cap B) . This gives,

\frac{26}{29}=\frac{7}{29}+\frac{24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{7+24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{31}{29}+P(A\cap B)\\\\P(A\cap B=\frac{31}{29}-\frac{26}{29}\\\\P(A\cap B=\frac{31-26}{29}=\frac{5}{29}

Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is \frac{5}{29}

6 0
3 years ago
AP calculus HW Need help on #61
Yuki888 [10]
Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x

Crossing the 1s , the 2xs, and the x^2s out, we get

(2x</span>∆x+∆x^2-2∆x)/<span>∆x

Dividing the </span><span>∆x, we get 
2x+</span><span>∆x-2. 

Making the limit of </span><span>∆x=0, we get 2x-2.</span>
7 0
3 years ago
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