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LUCKY_DIMON [66]
2 years ago
10

What is a fraction that is more than 1/10 but less than 1/2

Mathematics
2 answers:
tatyana61 [14]2 years ago
7 0
This question makes no sense
emmainna [20.7K]2 years ago
3 0

Answer: 1/3

Step-by-step explanation:

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1 ten.

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1 ten = 10 ones/units

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Find the indicated angle measure.<br> Find mZFEH<br> F<br> G<br> 35<br> 40°<br> H<br> E
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E

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A colored ball was drawn out of a bag with replacement. What is
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Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)
DiKsa [7]

Answer:

The standard equation of the sphere is (x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Let the first endpoint be represented as (x_{1}, y_{1}, z_{1}) and the second endpoint be (x_{2}, y_{2}, z_{2}).

Hence,

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Midpoint = (\frac{3 + 7  }{2}, \frac{-2+12 }{2}, \frac{4 + 4  }{2})

Midpoint = (\frac{10 }{2}, \frac{10}{2}, \frac{8  }{2})\\

Midpoint = (5, 5, 4)

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2}      }

d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}

d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}

d = \sqrt{16 +196 + 0

d =\sqrt{212}

d = 2\sqrt{53}

This is the diameter

To find the radius, r

From Radius = \frac{Diameter}{2}

Radius = \frac{2\sqrt{53} }{2}

∴ Radius = \sqrt{53}

r = \sqrt{53}

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is (5, 5, 4)

Radius of the sphere is \sqrt{53}

The equation of a sphere of radius r and center (h,k,l) is given by

(x-h)^{2} + (y-k)^{2} + (z-l)^{2}  = r^{2}

Hence, the equation of the sphere of radius \sqrt{53} and center (5, 5, 4) is

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = \sqrt{(53} )^{2}

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

This is the standard equation of the sphere

6 0
3 years ago
A right angled triangle has two shorter sides and one is twice as long as the other. The hypotenuse is 25cm long. What are the l
Bas_tet [7]

Answer:  x =  14.43

Step-by-step explanation:

The Pythagorean Theorem states the following:  

a^2 + b^2 = c^2  

Make one side of the triangle x  

Make the second side of the triangle 2x  

Now, you can plug the values into the equation,  right?  

x^2 + 2x^2 = 25^2 or 625  

3x^2 = 625

Divide each side by 3 and you are left with:  

x^2 =  208.33

Now, take the square root of 208.33

x =  14.43

That is the shorter side. The longer side is twice that value: Therefore, 14.43 x 2 = 28.86 14.43 is one side of the triangle. The other is that same value times two. Therefore, the sides of your triangle are: 14.43 Shorter side 28.86 Longer side

5 0
3 years ago
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