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3 years ago

PLeAsE sEnD hElP !!!!!!!!!!!!!!!!

Mathematics

1 answer:

Luba_88 [7]3 years ago

3 0

Answer:

5 units

Step-by-step explanation:

If DG, EG and FG are perpendicular bisectors of the sides of triangle ABC, then point G is the circumcenter of the triangle ABC and

BG = AG = CG as radii of the circumcirle.

Consider right triangle BEG. By the Pythagorean theorem,

$BG^2=EG^2+BE^2\\ \\BG^2=4^2+3^2\\ \\BG^2 =16+9\\ \\BG^2=25\\ \\BG=5\ units$

This gives us that

AG = BG = 5 units

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I need 1 answer for 99 points

Nataly [62]

Answer:

$7.45

Step-by-step explanation:

If it's constant , divide the amount he earns by the amount of hours. It should be the same every time.

44.70 divided by 6=7.45

and so on

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2 years ago

Read 2 more answers

For f(x) = 3x^2 + 2x - 1, identify the rule for g(x) = f(x + 1) - 6 and it's graph.

PilotLPTM [1.2K]

2x2 + x −#6 _____________

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∙ x

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Rewrite as multiplication.

(2x − 3)(x + 2) __

(x + 1)(x − 1) ∙ (x + 1)(x + 1) __ (x + 2)(x − 2) Factor the numerator and denominator.

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4 0

3 years ago

Line d is parallel to line c in the figure below Which statements about the figure are true? Select three options

Marianna [84]

Line d and c are bother parallel but the three options would be them

4 0

3 years ago

For the following amount at the given interest rate compounded continuously, find (a) the future value after 9 years, (b) the

Stella [2.4K]

Answer:

(a) The future value after 9 years is $7142.49.

(b) The effective rate is $r_E=4.759 \:{\%}$ .

(c) The time to reach $13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of $P$ dollars is invested at a rate of interest $r$ compounded continuously for $t$ years, the compound amount is

$A=Pe^{rt}$

(a) From the information given

$P=4700$

$r=4.65\%=\frac{4.65}{100} =0.0465$

$t=9 \:years$

Applying the above formula we get that

$A=4700e^{0.0465\cdot 9}\\A=7142.49$

The future value after 9 years is $7142.49.

(b) The effective rate is given by

$r_E=e^r-1$

Therefore,

$r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}$

(c) To find the time to reach $13,000, we must solve the equation

$13000=4700e^{0.0465\cdot t}$

$4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88$

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3 years ago

I would appreciate it if someone helped me:)

Evgesh-ka [11]

Answer:

24 more chocolotae chip cookies are sold

Step-by-step explanation:

CCC 7(15)+6 105+6=111

SC 6(15)-3 90-3 = 87

111-87 = 24

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2 years ago