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lina2011 [118]
3 years ago
13

Cine ma poate ajuta?

Mathematics
1 answer:
stira [4]3 years ago
5 0

Answer:

u think its A if not sorry

Step-by-step explanation:

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What is the first step in solving ln(x − 1) = ln6 − lnx for x?
Stels [109]

Answer:

Option C - Simplify the right side using the "difference of two logs is the log of the quotient" property.

Step-by-step explanation:

Given : Expression \ln (x-1)=\ln 6-\ln x

To find : What is the first step in solving  the expression ?

Solution :

Expression \ln (x-1)=\ln 6-\ln x

Step 1 - Simplify the right side using the "difference of two logs is the log of the quotient" property.

i.e. \ln a-\ln b=\ln(\frac{a}{b})

Apply the first step we get,

\ln (x-1)=\ln(\frac{6}{x})

Therefore, Option C is correct.

6 0
3 years ago
Which of these numbers is divisible by 2 A. 2612 B.1241 C.4263
julia-pushkina [17]

Answer:

A. 2612

cause 2612 is a even number

6 0
3 years ago
What’s the answer to this?
Elina [12.6K]

Step-by-step explanation:

Line is passing through the points:

(-2,\:3)=(x_1,\:y_1) \:\&\: (2,\:5)=(x_2 ,\:y_2)

Equation of line in two point form is given as:

\frac{y -y_1 }{y_1 -y_2 } = \frac{x -x_1 }{x_1 -x_2 } \\ \\ \therefore \frac{y -3}{ 3 -5} = \frac{x -(-2) }{-2 -2} \\ \\ \therefore \frac{y -3}{ - 2} = \frac{x -(-2) }{-4} \\ \\ \therefore \frac{y - 3}{1} = \frac{x +2}{2} \\ \\ \therefore \: y-3= \frac{x}{2} + \frac{2}{2} \\ \\\therefore \: y= \frac{x}{2} + 1 +3\\ \\ \huge \red{ \boxed{\therefore \: y= \frac{1}{2} \:x+ 4}}\\ is \: the \: required \: equation \: of \: line.

4 0
3 years ago
A garden is shaped like a rectangle whose perimeter is 150 ft. The length is 2 times as long as the width. Find the length and t
vlabodo [156]

Answer:

Step-by-step explanation:

L=2W

P=2(L+W), using L=2W this becomes

P=2(2W+W)

P=2(3W)

P=6W, given P=150

6W=150

W=25, and since L=2W

L=50 so

L=50ft and W=25ft

6 0
3 years ago
Part one: Solve the standard form for the equation of a line for x.
vichka [17]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
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