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asambeis [7]
2 years ago
13

Please help me with this question

Mathematics
1 answer:
MissTica2 years ago
7 0

Answer:

119

Step-by-step explanation:

64 + 23 + 32

119 I think

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Which table does not represent a linear function?
maks197457 [2]

Answer:

D . . . (it represents a quadratic function)

Step-by-step explanation:

The x-values are 1 unit apart for all values in all tables, making the problem much simpler. All you need to do is find the table where the y-value differences are not the same from one line to the next.

In table A, y-values decrease by 3.

In table B, y-values increase by 5.

In table C, y-values increase by 1.

In table D, y-values increase by 3, 2, 1—numbers that are not constant. (These differences decrease by 1, a number that *is* constant. Since the 2nd differences are constant, the table represents a 2nd degree function.)

3 0
3 years ago
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Use the complement to find the probability. Enter your answer in simplified fraction form.
Ket [755]
2/3 or 66.666666...% is the probability of it not landing on blue
6 0
2 years ago
I NEED HELP! If f(x)= 5x^2-3 and g(x)=x^2-4x-8, find (f-g)(x).
yaroslaw [1]

Answer:

(f - g)(x) = 4x² + 4x + 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 5x² - 3

g(x) = x² - 4x - 8

(f - g)(x) is f(x) - g(x)

<u>Step 2: Find (f - g)(x)</u>

  1. Substitute:                    (f - g)(x) = 5x² - 3 - (x² - 4x - 8)
  2. Distribute -1:                 (f - g)(x) = 5x² - 3 - x² + 4x + 8
  3. Combine like terms:    (f - g)(x) = 4x² + 4x + 5
5 0
2 years ago
Lowest common factor of 6 and 12
xxTIMURxx [149]

Answer:

36

Step-by-step explanation:

It's so obvious lollllll

5 0
2 years ago
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Help me plz the 1 photo is the question the second photo is the answer choices
Naddika [18.5K]

Answer:

D. on Tuesday the doctor saw one more patient per hour.

Step-by-step explanation:

on Monday for one hour he had 3 patients but on Tuesday for one hour he had 4 patients and so forth

hope this helps :)

4 0
3 years ago
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