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1 answer:
We can solve this problem by seeing at which part both of the parts of the graphs of the function are discontinued. Both of the parts of the graph of the function are discontinued at -2, so we will have to find a function that has a value that is undefined for x = -2. We can do this using the denominator of the fraction that's in each of the functions. The function where x = -2 will cause it to be undefined is the third one, so the answer to this question is C., f (x) = 
+5.
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Answer:
y = 2 + ((-)6/5)x
Step-by-step explanation:
-6x-5y=-10
add 6x to both sides.
-5y = -10 +6x
divide both sides by -5
y = 2 - (6/5)x
Plug in 0 for x to get the y intercept:
f(0) = 2 - (6/5) (0)
y = 2
(0, 2) is the y intercept.
Do the same for values such as -1, -2, 1, and 2, etc.
Then graph it.
