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ira [324]
3 years ago
7

Find the square roots of the two factors of √36 and multiply them.​

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0

Answer:

The square root is 6.

Step-by-step explanation:

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Can someone help me
Alex_Xolod [135]

Answer:

Su=10

Explaination:

So from s to u on the nunebr line is worth 2x-12. So what is s to u worth? Well. S to t on the number line = x-7. T to u =6. And 2 x is worth 12 more than s to u, using th e expression. X has to be at least 8 because otherwise the x-7 wouldn't work, and u might get s to u = 0 or a negative number.

Say x was 13, then 13 - 7 =6. So S to t =6. And r to u =6. So s to u =12. (6+6). Then check if the expression fits this answer of 12. 2x - 12. 2x = 26. 26-12=14, which doesn't match.

Let's try 14. 14-7=7. Then s to u = 7+6=13. The expression: 2x= 28. 28-12=16. 13 and 16 dont match. So we have got further away from what we need. Why don't we try going in the opposite direction. Rather than testing 13 and +1, let's now - 1 and try 12.

If x=12, then s to t =12-7=5. And s to u =6+5=11. The expression: 2x=24.-12=12. We are very close now with 11 and 12.

Lets test x=11!

S to t = 11-7=4. 4+6=10. So s to u =10.

2x=22. 22-12=10. So the expression works and the number line measurements.

The answer is su=10 and x=11.

3 0
3 years ago
Help and please number the answers accurately thanks a lot!
kvasek [131]

Answer:

I KNOWW THE ANSWER!!

Step-by-step explanation:

7 0
2 years ago
17. Find the measures of the length and width of
777dan777 [17]

Answer:

can you click a full photo of this question.

7 0
3 years ago
ANSWER AS MANY THROUGH 1 and 9 FOR 15 POINTS
Tamiku [17]
Number 9 is 1.52 because you divide 15.3 by 10 it will be 1 .52
7 0
3 years ago
what �is the equation of a line that is perpendicular to the line  y = − 2 5 x − 5 y = - 2 5 x - 5 and passes thr
gladu [14]

Answer:

y=\frac{1}{25}x-\frac{31}{25}

Step-by-step explanation:

y=-25x-5

You can get the gradient of the line perpendicular to this as you know the products of their gradients will be -1.

-25*m_{perpendicular}=-1\\m_{perpendicular}=\frac{1}{25}

We have a gradient, and a point (6, 1), so we can now substitute our known values into the line equation.

(y-y_0)=m(x-x_0)

y-1=\frac{1}{25} (x-6)

Rearrange for y and collect terms.

y=\frac{1}{25}x-\frac{6}{25}-1\\\\y=\frac{1}{25}x-\frac{31}{25}

8 0
3 years ago
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