1.50 + 0.50(x-1) <u><</u> 25
1.50 + 0.50x - 0.50 <u><</u> 25
1 + 0.50x <u><</u> 25
<u>-1 -1</u>
0.50x <u><</u> 24
<u> ÷0.50 ÷0.50</u>
x <u><</u> 48
1.50 + 0.50x <u><</u> 25 ; x <u><</u> 47 miles 3rd option in the choices.
To check:
1.50 + 0.50(47) <u><</u> 25
1.50 + 23.50 <u><</u> 25
25 <u><</u> 25
(-5,2) concave up
Hope this helps :)
Answer:
One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:
Iaₙ₊₁I < IaₙI
This means that the absolute value of the terms must decrease as n increases.
Then we must have:

We can write this as:

If we assume that n is a really big number, then:
n + 1 ≈ 1
And we can write:

Then we have the inequality

And remember that this must be in absolute value, then we will have that:
-1 < (x - 2)/3 < 1
-3 < x - 2 < 3
-3 + 2 < x < 3 + 2
-1 < x < 5
The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.
Answer: C
Step-by-step explanation: 1/3 probability
Answer:
Present value = $4,122.4
Accumulated amount = $4,742
Step-by-step explanation:
Data provided in the question:
Amount at the Start of money flow = $1,000
Increase in amount is exponentially at the rate of 5% per year
Time = 4 years
Interest rate = 3.5% compounded continuously
Now,
Accumulated Value of the money flow = 
The present value of the money flow = 
= 
= ![1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4](https://tex.z-dn.net/?f=1000%5Cleft%20%5B%5Cfrac%7Be%5E%7B0.015t%7D%7D%7B0.015%7D%20%5Cright%20%5D_0%5E4)
= ![1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]](https://tex.z-dn.net/?f=1000%5Ctimes%5Cleft%20%5B%5Cfrac%7Be%5E%7B0.015%284%29%7D%7D%7B0.015%7D%20-%5Cfrac%7Be%5E%7B0.015%280%29%7D%7D%7B0.015%7D%20%5Cright%5D)
= 1000 × [70.7891 - 66.6667]
= $4,122.4
Accumulated interest = 
= 
= $4,742