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3 years ago

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10 years ago, Rapunzel had 19 centimeters of hair, now her hair is 20,193 centimeters long, how long has her hair grown? in scie

ntific notation-
1) 1*10^3
2) 2*10^3
3) 1*10^5
4) 2*10^5

1 answer:

zhuklara [117]3 years ago

5 0

Answer:

Approximately 1*10^3

Step-by-step explanation:

20,193/19=1,062

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Can someone answer this question please?

allochka39001 [22]

Answer:

Step-by-step explanation:9

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3 years ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

3 years ago

What are RQS and TQS?

yaroslaw [1]

Answer:

m∠RQS = 72°

m∠TQS = 83°

Step-by-step explanation:

m∠RQS +m ∠TQS = m∠RQT

The two angles combine to make a larger angle

So

m∠RQS = (4x - 20)

m∠TQS = (3x + 14)

(4x - 20) + (3x + 14) = 155

Group the Xs and the constants

4x + 3x - 20 + 14 = 155

Combine like terms

7x - 6 = 155

Add 6 to both sides

7x = 161

Divide by 7 on both sides

x = 23

Check:

4(23) - 20 + 3(23) + 14 = 155

92 - 20 + 69 + 14 = 155

155 = 155

But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.

m∠RQS = 4(23) - 20 = 72°

m∠TQS = 3(23) + 14 = 83°

Checking:

72 + 83 = 155

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3 years ago

A booklet is made from 6 rectangular pieces of paper. Each piece measures 297mm by 420mm. The mass of paper is 80g per m^2. What

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748440mm^2*1m^2/1,000,000mm^2=0.748440m^2 by crossing out the millimeters. Lastly, since it's 80g/1m^2, we multiply our number by that to get 59.8752g

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Answer:

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