Therefore, the sentence "A triangle is isosceles if and only if it has two congruent (equal) sides" is <span>biconditionaL</span>
The equation of a circle centred at point (m,n) and radius r is given by
<span>(x-m)² + (y-n)² = r²
</span>-------------------------------------------------------------
Centre = (4,3)
radius = 5
Equation:
(x - 4)² + (y - 3)² = 5²
⇒ x² - 8x + 16 + y² - 6y + 9 = 25
⇒ x² + y² - 8x - 6y + 25 = 25
⇒ x² + y² - 8x - 6y = 0
The equation of the circle is x² + y² - 8x - 6y = 0
Hope it helps!
Answer:
−y−1=3
Step-by-step explanation:
Which equation can be used to find the solution of (1/4)^y+1=64?
This can be solved by power of indices
(1/4)^(y+1)=64
(4^-1)^(y + 1)= 4^3
Note
(x^a)^b = x^ab
Hence:
4^(-1)(y + 1)= 4^3
4^-y - 1 = 4^3
Divide both sides by 4
−y−1=3
Hence, the equation that can be used to find the solution of (1/4)^y+1=64 is
−y−1=3
