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BabaBlast [244]
2 years ago
10

Alejandro will deposit $1,750 in an account that earns 6.5% simple interest every year. His sister Anallency will deposit $1,675

in an account that earns 7.5% interest compounded annually. The deposits will be made on the same day, and no additional money will be deposited or withdrawn from the accounts. Which sibling will have more money at the end of four years?
Mathematics
2 answers:
ivann1987 [24]2 years ago
6 0

Answer: Anallency

Step-by-step explanation:

First, lets make two equations for both siblings, using the base: SI = P(1 + rt) and CI = P(1 + r/n)^nt

Alejandro = 1750(1 + 0.065[4]) = 1750 + 455 = $2,205

Anallency = 1675(1 + 0.075/1)^4 = $2236.91

After 4 years, Alejandro will have $2,205, and Anallency will have $2236.91

Since $2236.91 > 2,205, Anallency will have more money after 4 years.

kogti [31]2 years ago
5 0

Answer:

Anallency will have mor money.

Step-by-step explanation:

Simple Interest:

I = Prt

I = $1750 × 0.065 × 4

I = $455

Total after 4 years: $1750 + $455 = $2205

Compound Interest:

F = P(1 + r/n)^(nt)

F = $1675(1 + 0.075)^(4)

F = $2236.91

Answer: Anallency will have mor money.

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Answer:

15.71

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Put in circumference formula C=2πr

c=2 x 3.14 x 2.5

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Which expression is<br> equivalent to the following complex fraction?
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(y - x)/(y + x)

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(1/x - 1/y)/(1/x + 1/y) =

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Given f (x) = -5x + 1, find f (6)
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Read 2 more answers
A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
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Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea
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Answer:

a) 17.5

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c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

\int\limits^y_0 {kx^{2} } \, =1

where y=23

Clearing k=0.00025

a) Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5

b)Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2}  =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6

c) The function is equal to:

f(x)=k(1+2x)

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3 years ago
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