Answer:
91
Step-by-step explanation:
p^6×q^12 will have (6+1)(12+1) = 7×13 = 91 positive integer divisors.
Answer:
8 * (7 + 4)
See process below
Step-by-step explanation:
We start by writing each number in PRIME factor form:
56 = 2 * 2 * 2 * 7
32 = 2 * 2 * 2 * 2 * 2
Notice that the factors that are common to BOTH numbers are 2 * 2 * 2 (the product of three factors of 2).Therefore we see that the greatest common factor for the given numbers is : 2 * 2 * 2 = 8
Using this, we can write the two numbers as the product of this common factor (8) times the factors that are left on each:
56 = 8 * 7
32 = 8 * 2 * 2 = 8 * 4
We can then use distributive property to "extract" that common factor (8) from the given addition as shown below:
56 + 32
8 * 7 + 8 * 4
8 * (7 + 4)
8 * (11)
88
Answer:
0,-8
-6,0
Step-by-step explanation:
Answer:
x^2+16x+64 is a perfect square
that is (x+a)^2=x^2+2ax+a^2
compare the coefficients of the x term
--> 2a=16 --> a=8
---> x^2+16a+64=(x+8)^2
plz mark me as brainliest :)
