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2 years ago

Answer and show work

Mathematics

2 answers:

sertanlavr [38]2 years ago

8 0

Answer:

3x+2/4>-20

3x+2>-80

3x>-80-2

3x>-82

x>-82/3

Also simplified to, x>-27 1/3

erastova [34]2 years ago

7 0

B is the correct answer

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qwelly [4]

Answer:

You look very nice!

Step-by-step explanation:

it matters what you look like to yourself not how you look to others!

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2 years ago

Which equation BEST represents the line of best fit for the scatterplot?

velikii [3]

Y=2x+2 describe the best fit.

first find x and y intercept of a line
x intercept where y=0 is x=-1 and y intercept where x=0 is y=2

6 0

2 years ago

Read 2 more answers

3 regions are defined in the figure find the volume generated by rotating the given region about the specific line

anastassius [24]

The volume generated by rotating the given region $R_{3}$ about OC is $\frac{4}{g} \pi$

<h3>Washer method</h3>

Because the given region ( $R_{3}$ ) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

$y=2(x)^{\frac{1}{4} }$

$x=(\frac{y}{2} )^{4}$

$y=2x$

$x=\frac{y}{2}$

$\int\limits^a_b {\pi } \, (R_{o^{2} } - R_{i^{2} } ) dy$

$R_{o} = x = \frac{y}{2}$

$R_{i} = x= (\frac{y}{2}) ^{4}$

$a=0, b=2$

$v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} ) dy$

$v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }} ] dy$

$v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]$

$v=\pi [\frac{1}{4} \frac{y^{3} }{3} \int\limits^2_0 - \frac{1}{2^{8} } \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi$

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

6 0

1 year ago

Select two choices that are true about the function f(x)=23x+14/x

WINSTONCH [101]

Answer:

There is an asymptote at x = 0

There is an asymptote at y = 23

Step-by-step explanation:

Given the function:

(23x+14)/x

Vertical asymptote is gotten by equating the denominator to zero

Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0

Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator

Coefficient of x at the numerator = 23

Coefficient of x at the denominator = 1

Ratio = 23/1 = 23

This means that there is an asymptote at y = 23

8 0

2 years ago

A rectangular sheet of paper has a perimeter of 60cm. When it is folded in half along its longer line of symmetry, the perimeter

Liula [17]

Answer:

Dimensions of the original rectangle:

Length = 19 cm

Width = 11 cm

Step-by-step explanation:

Let

Length = x

Width = y

Original rectangle:

2(Length + width) = 60

2x + 2y = 60

New rectangle has same length with original rectangle but half of the width of the original rectangle when folded

Length = x

Width = 1/2y

2(Length + 1/2width) = 49

2x + y = 49

2x + 2y = 60 (1)

2x + y = 49 (2)

Subtract (2) from (1) to eliminate x

2y - y = 60 - 49

y = 11

Substitute y = 11 into (2)

2x + y = 49

2x + 11 = 49

2x = 49 - 11

2x = 38

x = 38/2

x = 19

Dimensions of the original rectangle:

Length = 19 cm

Width = 11 cm

3 0

3 years ago