Company A has a sales position with a yearly salary of $42,000. Company B has a similar sales position with a slary of $39,000 plus 1% conmission on yearly sales.
Let x be the amount of yearly sales
Company A has a sales position with a yearly salary of $42,000.
yearly salary = 42,000
Company B has a similar sales position with a salary of $39,000 plus 1% commission on yearly sales.
1% is 0.01
yearly salary = 39,000+ 0.01x
yearly sales is the salary at company A greater than the salary and conmission at company B
A > B
42000 > 39000+ 0.01x
We solve the inequality
39000+ 0.01x < 42000
Subtract 39000 on both sides
0.01x < 3000
divide by 0.01
x> 300,000
For yearly sales > $300,000, the salary at company A greater than the salary and commission at company B
Answer:
(x-7) (x^2-5)
Step-by-step explanation:
x^3 -7x^2 -5x+35
Make 2 groups
x^3 -7x^2 -5x+35
Factor x^2 from the first group and -5 from the second group
x^2 (x-7) -5(x-7)
Now factor (x-7) out
(x-7) (x^2-5)
Answer:
Can you please organize this text.
Answer:
Part A: Rewrite the expression by factoring out the greatest common factor. (4 points)
answer:
2y(x³+4x-2x²-8)
Part B: Factor the entire expression completely. Show the steps of your work. (6 points)
answer:
2y(x³+4x-2x²-8)
2y(x³-2x²+4x-8)
2y(x²(x-2)+4(x-2))
2y(x²+4)(x-2)
