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Arlecino [84]
3 years ago
9

Brainliest is on the line here

Mathematics
1 answer:
xeze [42]3 years ago
6 0

1st : , Her parents didnt think much of it until she started to skip dinner with her family and even refused to go to school.'

2nd : , And with every post they make on their favorite social media site, they may be opening themselfs to all kinds of medical problems. '

brainliest<3?

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slava [35]
Its already fully simplified.
7 0
4 years ago
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What is the slope of the line that cuts through the points (1, -5) and (3, 5)?
PolarNik [594]

Answer:

a. 5

Step-by-step explanation:

To find slope, subtract the y's.

5 - -5 is 10.

Put that on the top of a fraction.

Subtract the x's.

3 - 1 is 2, put that on the bottom of the fraction.

So the slope is 10/2. This simplifies to 5 (because 10÷2 is 5).

The slope is 5.

8 0
2 years ago
The price p is less than or equal to $25
AleksandrR [38]

Answer:

Great question

Step-by-step explanation:

5 0
3 years ago
Nolan has some nickels and some dimes. He has no more than 19 coins worth no less than $1.30 combined. If Nolan has 5 nickels, d
Allushta [10]

Answer:

number of dimes 11 to 14

Step-by-step explanation:

given data

coin = 19

worth no less = $1.30

Nolan nickles = 5

solution

we convert 5 cent to dollars, it will be

5÷100 = $0.05

and

dime is worth 10 cents

so it will be 10 ÷ 100 = $0.1

so we consider here x as the number when nickels.

and we consider y as the number of dimes.

so here we can say

x + y ≤ 19      ..........................1

as here no less than $1.30 combined.

so

0.05 x + 0.1 y ≥ 1.3       ......................2

and

when Nolan has 5 nickels

put x = 5 in eq 1

5 + y ≤ 19  

y ≤ 19 - 5

y ≤ 14

and

now we put x = 5 in eq 2

0.05 × 5 + 0.1y ≥ 1.3

0.25 + 0.1y ≥ 1.3

0.1y ≥ 1.3 - 0.25

0.1y ≥ 1.05

y ≥ 10.5

so all possible values for the number of dimes 11 to 14

7 0
3 years ago
Given F ( x ) = -2/3 x - 4 What is the zero of this function?
sineoko [7]

Answer:

-4

Step-by-step explanation:

f(0)=(-2/3)(0) - 4

= - 4

5 0
3 years ago
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