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Setler [38]
1 year ago
12

What is the answer to 3x +5x

Mathematics
2 answers:
denis23 [38]1 year ago
8 0

Answer:

8x

Step-by-step explanation:

To do this we simply add the coefficients of x to give us our answer:

3 + 5 = 8

So our answer is 8x

One way to put this into perspective is to imagine x is the number of apples:

If you add 3 apples and 5 apples you get 8 apples.

Always do this trick when collecting like terms in algebra.

s344n2d4d5 [400]1 year ago
6 0
3x+5x= 8x
I hope this helps !!
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Is the m in mx+b=y the growth
Shalnov [3]

The "m" in y = mx + b is the <u>slope.</u>

It is the number of units a point goes up, down, left, or right each time. Making the line linear/straight.

m = \frac{rise}{run}

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For example, if your slope is:

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4 0
3 years ago
Read 2 more answers
Graph the equation by plotting three points. If all three are correct the line will appear -3y=-2x-6
Pachacha [2.7K]
Three possible points are:
(-3, 0)
(0, 2)
(3, 4)

To find any points, simply select any value for x. Input that value, then find the corresponding y-value.

For example, if x = 0, then:

-3y = -2(0) - 6
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3 0
3 years ago
GIVING AWAY A LOT POINTS! PLEASE ANSWER!
masya89 [10]

The slope of the line is “rise over run.” That’s the vertical change between the two points (the difference in the y-coordinates) divided by the horizontal change over the same segment (the difference in the x-coordinates).
6 0
3 years ago
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

7 0
3 years ago
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