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lilavasa [31]
3 years ago
10

A planet is most likely to have tectonic activity if it has:.

Physics
1 answer:
yuradex [85]3 years ago
4 0

Answer: Heyo Kenji Here! Here's your answer- A planet is most likely to have tectonic activity.

Explanation: Hope this helps!

Have a nice day!

- Kenji ^^

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the force has to be specified both in terms of its magnitude as well as its direction true or false? ​
Mamont248 [21]

Anwser

The strength of a force is usually expressed by its magnitude. We have also to specify the direction in which a force acts.

3 0
3 years ago
Read 2 more answers
Metal sphere 1 has a positive charge of 7.00 nc . metal sphere 2, which is twice the diameter of sphere 1, is initially uncharge
MariettaO [177]

Answer:

2.33 nC, 4.67 nC

Explanation:

when the two spheres are connected through the wire, the total charge (Q=7.00 nC) re-distribute to the two sphere in such a way that the two spheres are at same potential:

V_1 = V_2 (1)

Keeping in mind the relationship between charge, voltage and capacitance:

C=\frac{Q}{V}

we can re-write (1) as

\frac{Q_1}{C_1}=\frac{Q_2}{C_2} (2)

where:

Q1, Q2 are the charges on the two spheres

C1, C2 are the capacitances of the two spheres

The capacitance of a sphere is given by

C=4 \pi \epsilon_0 R

where R is the radius of the sphere. Substituting this into (2), we find

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 R_2} (3)

we also know that sphere 2 has twice the diameter of sphere 1, so the radius of sphere 2 is twice the radius of sphere 1:

R_2 = 2R_1

So the eq.(3) becomes

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 2R_1}

And re-arranging it we find:

Q_2 = 2Q_1

And since we know that the total charge is

Q_1 + Q_2 = 7.00 nC

we find

Q_1 = 2.33 nC\\Q_2 = 4.67 nC

3 0
4 years ago
In theory, what would be the approximate weight gain of a person who consumes an excess of 500 kcal every day for four weeks (e.
Neko [114]

Answer:Wait

Explanation:

give me time to think I am working on it

3 0
3 years ago
Match the synthetic materials with the processes used to make them.
BlackZzzverrR [31]
We can’t see anything
3 0
3 years ago
What potential difference is needed to stop an electron that has an initial velocity v=6.0
Assoli18 [71]

Formula for kinetic energy of an object:

KE = 0.5mv²

m is the mass and v is the velocity.

Formula for the work done on a charged object by moving it through a potential difference:

W = ΔVq

ΔV is the potential difference and q is the charge of the object.

To find the potential difference needed to decelerate an electron to rest, set the work done on the electron equal to its kinetic energy:

W = KE

Substitute W = ΔVq and KE = 0.5mv²

ΔVq = 0.5mv²

Given values:

q = 1.6×10⁻¹⁹C

m = 9.11×10⁻³¹kg

v = 6.0m/s

Plug in the given values and solve for ΔV

ΔV×1.6×10⁻¹⁹ = 0.5×9.11×10⁻³¹×6.0²

ΔV = 1.02×10⁻¹⁰V

7 0
3 years ago
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