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aleksandr82 [10.1K]
3 years ago
15

Give an example of Electrical Force

Physics
1 answer:
IgorC [24]3 years ago
4 0

Answer: Sometimes people try to use there flashlight but it doesnt turn on they take out there battierise and they rub them together. It doesnt work so they get new battiries

Explanation: please mark me brainlies i have a goal im tryna reach thank you!!

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A satellite is in a circular orbit 21000 km above the Earth’s surface; i.e., it moves on a circular path under the influence of
mina [271]

Answer:

(orbital speed of the satellite) V₀ = 3.818 km

Time (t) = 4.5 × 10⁴s

Explanation:

Given that:

The radius of the Earth is 6.37 × 10⁶ m;    &

the acceleration of gravity at the satellite’s altitude is 0.532655 m/s

We can calculate the orbital speed of the satellite by using the formula:

Orbital Speed (V₀) = √(r × g)

radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m

                                  = (2.1 × 10⁷ + 6.37 × 10⁶) m

                                  = 27370000

                                  = 2.737 × 10⁷m

Orbital Speed (V₀) = √(r × g)

Orbital Speed (V₀) = √(2.737 × 10⁷  × 0.532655 )

                              = 3818.215

                              = 3.818 × 10³

                             = 3.818 Km

To find the time it takes to complete one orbit around the Earth; we use the formula:

Time (t) = 2 π × \frac{r}{V_o}

            = 2 × 3.14 × \frac{2.737*10^7}{3.818*10^3}

            = 45019.28

            = 4.5 × 10 ⁴ s

6 0
3 years ago
Please help this is for my final exam
ki77a [65]

Answer:

A

Explanation:

5 0
3 years ago
Can sound travel through a tree
Marizza181 [45]

Answer:

not sure but i think yes

Explanation:

sound waves

7 0
2 years ago
Read 2 more answers
If R1 and R2 are in parallel and R3 is in series with them then equivalent resistance will be
pochemuha

Answer:

Refer to the attachment!~

5 0
3 years ago
A spring (70 N/m ) has an equilibrium length of 1.00 m. The spring is compressed to a length of 0.50 m and a mass of 2.0 kg is p
madreJ [45]

Answer:

Part a)

L = 0.68 m

Part b)

L = 0.63 m

Explanation:

Part a)

As we know that there is no friction in the path

So here we can use energy conservation to find the distance moved by the mass

Initial spring energy = final gravitational potential energy

so we will have

\frac{1}{2}kx^2 = mgL sin\theta

\frac{1}{2}70(0.5)^2 = 2(9.81)(L) sin41

8.75 = 12.87 L

L = 0.68 m

Part b)

Now if spring is connected to the block then again we can use energy conservation

so we will have

\frac{1}{2}kx^2 = mg(x + x')sin\theta + \frac{1}{2}kx'^2

so we will have

\frac{1}{2}(70)(0.5^2) = 2(9.81) (0.50 + x') sin41 + \frac{1}{2}(70)x'^2

8.75 = 6.43 + 12.87 x' + 35 x'^2

x' = 0.13 m

so total distance moved upwards is

L = 0.5 + 0.13 = 0.63 m

8 0
3 years ago
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