20h
Explanation:
Given parameters:
Electrical power = 75W
Electrical energy = 1500J
Unknown:
Time taken = ?
Solution:
Electrical power is the amount of voltage that drives current.
P = IV
Electrical energy is the voltage that drives a current per unit of time
E = IVt
E = Pt
Since time is the unknown, we can make it subject of the formula;
t =
=
= 20h
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Invention of electrical power brainly.com/question/13146914
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That's 1/2 of what it is on the surface.
The distance between the center of the Earth and any object
on the surface is 1 Earth radius ... about 3960 miles.
Gravitational force is inversely proportional to the square of
the distance between the centers of the objects, so in order
to reduce the acceleration of gravity by 1/2, you increase the
distance by √2 .
(3960 miles) x (√2) = 5,600 miles from the center
= 1,640 miles above the surface.
Answer:
ITS THE LAST ONE(4TH), I THINK
Explanation:
Answer:

Explanation:
We apply Newton's second law at the crate :
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Data:
m=90kg : crate mass
F= 282 N
μk =0.351 :coefficient of kinetic friction
g = 9.8 m/s² : acceleration due to gravity
Crate weight (W)
W= m*g
W= 90kg*9.8 m/s²
W= 882 N
Friction force : Ff
Ff= μk*N Formula (2)
μk: coefficient of kinetic friction
N : Normal force (N)
Problem development
We apply the formula (1)
∑Fy = m*ay , ay=0
N-W = 0
N = W
N = 882 N
We replace the data in the formula (2)
Ff= μk*N = 0.351* 882 N
Ff= 309.58 N
We apply the formula (1) in x direction:
∑Fx = m*ax , ax=0
282 N - 309.58 N = 90*a
a= (282 N - 309.58 N ) / (90)
a= - 0.306 m/s²
Kinematics of the crate
Because the crate moves with uniformly accelerated movement we apply the following formula :
vf²=v₀²+2*a*d Formula (3)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
v₀ = 0.850 m/s
d = 0.75 m
a= - 0.306 m/s²
We replace the data in the formula (3)
vf²=(0.850)²+(2)( - 0.306 )(0.75 )


Answer:
if your bedroom is empty yes but if not most likely no
Explanation:
Why Cannot we hear an echo in a small room?
They can't hear an echo in small room because in it the sound can't be reflected back. For an echo of a sound to be heard,the minimum distance between the source of sound and the walls of the room should be 17.2 m.Obviously,in a small room echoes cannot be heard.