4 years ago

A 1613 kg car moves with a velocity of 9 m/s. What is its kinetic energy?

Physics

1 answer:

ryzh [129]4 years ago

4 0

We Know,

K.E. = 1/2 mv²

K.E. = 1/2 (1613)(9)²

K.E. = 1/2 * 1613*81

K.E. = 65326.5 Kgm/s

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Find the uncertainty in a calculated electrical potential difference from the measurements of current and resistance. Electric p

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Answer:

The value is $\Delta V = 11.5 \ V$

Explanation:

From the question we are told that

The formula for the Electric potential difference is $V = IR$

The current is $I = 9.3 \ A$

The uncertainty of the current is $\Delta I = 0.3 \ A$

The Resistance is $R = 19.7\ Ohms$

The uncertainty of the Resistance is $\Delta R = 0.6 \ Ohms$

Taking the log of both sides of the formula

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So from

$\Delta V = V * [\frac{\Delta I}{I} +\frac{\Delta R}{R} ]$

$\Delta V = 183.21 [ \frac{0.3 }{9.3} + \frac{0.6}{19.7}]$

=> $\Delta V = 11.5 \ V$

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