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denis23 [38]
2 years ago
15

How many, Inch cubes fit into a rectangular prism that measures 4 Inches long, 5 Inches wide, and

Mathematics
1 answer:
kramer2 years ago
8 0
780 (or c)


I think this is correct because 4 x 5 = 20 x 5 = 100 and 100 x 5 = 500

500 + 280 = ????

780
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If c varies directly as (r + 1) and c = 8, when r= 3, calculate the value of r when c= 20.
Aneli [31]

Answer:

r = 9

Step-by-step explanation:

Given that c varies directly as (r + 1) then the equation relating them is

c = k(r + 1) ← k is the constant of variation

To find k use the condition c = 8 when r = 3, then

8 = k(3 + 1) = 4k ( divide both sides by 4 )

2 = k

c = 2(r + 1) ← equation of variation

When c = 20, then

20 = 2(r + 1) ← divide both sides by 2

10 = r + 1 ( subtract 1 from both sides )

9 = r

5 0
3 years ago
Read 2 more answers
Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. n^2+5/2n
Sergeeva-Olga [200]

Answer:  \bigg(n+\dfrac{5}{4}\bigg)^2

<u>Step-by-step explanation:</u>

n^2+\dfrac{5}{2}n+\underline{\qquad}\\\\\\n^2+\dfrac{5}{2}n+\bigg(\dfrac{5}{2\cdot 2}\bigg)^2\\\\\\n^2+\dfrac{5}{2}n+\bigg(\dfrac{5}{4}\bigg)^2\\\\\\=\bigg(n+\dfrac{5}{4}\bigg)^2

5 0
3 years ago
8t-9 is less than or equal to 79
sattari [20]

Answer:

t ≤ 11 (or all values 11 or less)

Step-by-step explanation:

8t - 9 ≤ 79

<em>So, I am assuming you are trying to find the value(s) of "t".</em>

Add 9 to both sides.

8t ≤ 88

Divide 8 by both sides.

t ≤ 11

ANSWER

t ≤ 11

8 0
3 years ago
A tile installer charges $12 per square foot to install floor tile. What is the cost to install tile in a room of the size shown
babunello [35]

Answer: $480.00

Step-by-step explanation:

6 0
3 years ago
Help me pls<br><br> What is a visual Overlap
PilotLPTM [1.2K]
Informally assess the degree of visual overlap of two numerical data distributions with similar variabilities, measuring the difference between the centers by expressing it as a multiple of a measure of variability.


- Hope this helps!
4 0
3 years ago
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