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makvit [3.9K]
4 years ago
14

When pouring water from one five gallon bucket to another, a person tends to pour at a faster rate at first and then slow down i

n order not to spill. The amount of water left in the original bucket can be approximated by
f(t) = 5 - 0.82t0.62,
where f(t) is measured in gallons and t is the time spent pouring in seconds. Find the approximate amount of water left in the original bucket after 6 seconds of pouring. Round to the nearest hundredth.
Mathematics
1 answer:
Nitella [24]4 years ago
4 0

I will assume that 0.62 is an exponent   then

amount left  after t seconds = f(6) =   5 - 0.82(6)^0.62

= 2.51 gallons to nearest hundredth.

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Since, the dilation is the enlargement of the image in the same shape but different size.

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\begin{aligned}A^{\prime} C^{\prime} &=\sqrt{(-4+7)^{2}+(3-6)^{2}} \\&=\sqrt{3^{2}+(-3)^{2}} \\&=\sqrt{9+9} \\&=\sqrt{18}\\&=3\sqrt{2} \end{aligned}

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\begin{aligned}A C &=\sqrt{(-12+21)^{2}+(9-18)^{2}} \\&=\sqrt{9^{2}+(-9)^{2}} \\&=\sqrt{81+81} \\&=\sqrt{162}\\&=9\sqrt{2} \end{aligned}

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\frac{A'C'}{AC} =\frac{3\sqrt{2} }{9\sqrt{2}} =\frac{1}{3}

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