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OverLord2011 [107]
1 year ago
5

HELP ME PLEASEEEEEEEEEEEEEEEEEEEE

Mathematics
1 answer:
aev [14]1 year ago
7 0
Ooo substitution! I love this!

To solve this, we will substitute for y:

4/9x - 3 = -7/5x - 3

Jk. I’ll give you the answer to save time. The answer is x = 0.
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If the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3
horrorfan [7]

Answer:  The correct option is (B) 24 : 25.

Step-by-step explanation:  Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.

We are to find the ratio of the area of R to the area of S.

Let 2x, 3x be the sides of rectangle R and y be the side of square S.

Then, according to the given information, we have

\textup{Perimeter of rectangle R}=\textup{Perimeter of square S}\\\\\Rightarrow2(2x+3x)=2(y+y)\\\\\Rightarrow 5x=2y\\\\\Rightarrow \dfrac{x}{y}=\dfrac{2}{5}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Therefore, the ratio of the area of R to the area of S is

\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.

Thus, the required ratio of the area of R to the area of S is 24 : 25.

Option (B) is CORRECT.

6 0
3 years ago
What is 3/4 h = – 45/52
sergiy2304 [10]
Mixed number form: h = - 1 2/13 Hope that helps :))

6 0
3 years ago
A⋅a/\2⋅a/\3=?? I need help ASAP
wolverine [178]

Answer:

a^6

Step-by-step explanation:

a^1 * a^2 * a^3 = 1+2+3(add all power when same variable)

a^6

7 0
3 years ago
Find f(2) if f(x)= (x +1)^2
Drupady [299]

Answer:

9

Step-by-step explanation:

substitute the x which is x= 2, so

f(2)= (2+1)^2

=(3)^2

=9

6 0
1 year ago
Read 2 more answers
the standard addition algorithm below is being used to add three two-digit numbers 4z + 27 + x 5 equals y 14. If x, y, and z eac
Studentka2010 [4]
For the units positions of all numbers we have:
z+7+5=4 \\ z+12=4
From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:
z+12=14 \\ z=2

For the tens positions of all numbers we have:
4+2+x+1=1 \\ 7+x=1
The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.
7+x=11 \\ x=4

Now we insert x and z to find out y:
42+27+45=y14 \\ 114=y14 \\ y=1

Now we need to find out the product of these three numbers:
x*y*z=4*1*2=8
3 0
3 years ago
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