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2 years ago

HELP ME PLEASEEEEEEEEEEEEEEEEEEEE

Mathematics

1 answer:

aev [14]2 years ago

7 0

Ooo substitution! I love this!

To solve this, we will substitute for y:

4/9x - 3 = -7/5x - 3

Jk. I’ll give you the answer to save time. The answer is x = 0.

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A number line has marks A question mark, negative 2, B question mark, 0, 1, C-2, 3, D question mark, 5, E 6.

slavikrds [6]

Answer:

What number is represented by point B = -1

Which point represents the number 2? = C

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3 years ago

Read 2 more answers

Prove that 7-4√7 is irrational

mixas84 [53]

Answer:

hey ;

$7 - 4 \sqrt{7}$

is an irrational number

Step-by-step explanation:

here's the proof in attachment.

i hope it helped........

3 0

3 years ago

Please help radical expression dividing

77julia77 [94]

$\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}$

$\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}$

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.

6 0

3 years ago

A student is attempting to simplify the expression below. Sample mathematical work is shown. Which statement best applies to the

12345 [234]

The answer is A) The student failed to properly apply the distributive property.

4 0

4 years ago

Can someone help me with this question?

nevsk [136]

Step-by-step explanation:

1. Vertical

2. Alternate

3. congruent

4. AAS or SAA

7 0

3 years ago