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2 years ago

Are the ratios 20:16 and 5:4 equivalent?

Mathematics

1 answer:

emmasim [6.3K]2 years ago

5 0

Answer:

Yes

Step-by-step explanation:

20:16

Reduce the ratio to lowest terms by dividing both numbers by 4.

20:16 = 5:4

Answer: Yes

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How to find the number of sides of a polygon when given the interior angle sum

wariber [46]

Given:

Sum of interior angle

To find:

Number of sides of a polygon

Solution:

Using sum of interior angles formula:

$$S=(n-2) \times 180^{\circ}$

where "S" is the sum of interior angels and "n" is the number of sides of a polygon.

Divide by 180° on both sides.

$$\frac{S}{180^{\circ}}=\frac{(n-2) \times 180^{\circ}}{180^{\circ}}$

Cancel common factor 180°.

$$\frac{S}{180^{\circ}}=n-2$

Add 2 on both sides.

$$\frac{S}{180^{\circ}}+2=n-2+2$

$$\frac{S}{180^{\circ}}+2=n$

Switch the sides.

$$n=\frac{sum}{180^{\circ}}+2$

Therefore number of sides of a polygon is $n=\frac{sum}{180^{\circ}}+2$ .

3 0

3 years ago

Can someone pleeeeease help me!!

charle [14.2K]

Answer:

I’m pretty sure it’s 73% but I’m not completely sure

6 0

3 years ago

Plz help me out quick

natima [27]

Answer: 6:5

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Write an equation for the line in slope- intercept form. 2. Х -4 -2 o 2 4. -2 4

Alla [95]

Answer:

y= -2x-3

Step-by-step explanation:

this is because the y intercept is at negative 3 and the rise over run is down 1 over 2

3 0

2 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

2 years ago