432 characters can be expected to fit per yard of text. The following solution can be used:
Let x be the number of characters to be used in a yard
12 characters / in = x/ 36 in
(12 characters * 36 in) / in = x
x = 432 characters
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Answer:
(sin^2 w + 1) / cos w.
Step-by-step explanation:
Note: sec w = 1 / cos w and csc w = 1/ sin w.
So we have:
(sec w(1 + csc^2 w)) / (csc^2 w)
= 1/cos w ( 1 + 1/ sin^2 w) / (1 / sin^2 w)
= ( 1/ cos w + 1 / sin^2 w cos w) * sin^2 w
= sin^2 w/ cos w + sin^2 w / (sin^2 w cos w)
= sin^2 w / cos w + 1 / cos w
= (sin^2 w + 1) / cos w.
Answer
1.15 hours
Step-by-step explanation:
Assuming 115 is 115 km then you just move the decimal point twice and get 1.15!
For example - (Starting number) 115. (Moving decimal point) 115. -> 11.5 -> 1.15
Answer:
9 is an odd number and 8 is an even number.
