Answer:
C 10 in
Step-by-step explanation:
side of P is = 6
side of Q is = 8
for missing side use Pythagorean theorem
=
r^{2} = 36 + 64
r^{2} = 100
r = 10 in
Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
It is a combination answer
495 ways
Step-by-step explanation:
In this question, we are tasked with calculating the number of ways in which a manager can select 4 people out of 12 for the Sunday evening shift.
Firstly, the question talks about selecting a particular number from a mix, this is a combination question since the key word SELECT is mentioned.
Now, how do we go about it? To select a partial number from a mix , we use the combination formula as stated.
Mathematically, say we are selecting a number r from a total of numbers n, the number of ways we can do this is nCr = n!/(n-r)!r!
In this case however, we are simply selecting 4 out of 12
Our combinational equation thus becomes 12C4 = 12!/(12-4)!4! = 12!/8!4! = 495 ways
To find<span> the </span>area<span> of a rectangle multiply its height by its width. For a square you only need to </span>find<span> the length of one of the sides (as each side is the same length) and then multiply this by itself to </span>find<span> the </span>area<span>.</span>
Answer:
The GCF of 16 and 32 is 16.
Step-by-step explanation:
The GCF (greatest common factor) is the largest number that both numbers can be divided by.
16 is divisible by 16, which is the largest number 16 is divisible by. 32 is divisible by 16 as well, so the GCF of 16 and 32 is 16.