Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18 X P = 12 Radii of the circles are: 12, 8 and 6.
Distance =rate/time so your answer is 3 hours first you have to convert meters to kilometers 921000 meters = 921 Km so you have like terms to calculate so your distance becomes 921 Km then divide by the speed 907÷3 = 3 so your answer is 3 hrs
You will need to convert them into improper fractions, subtract them, and convert them back to mixed numbers. 5 1/8 - 2 4/8 41/8 - 20/8 21/8 2 5/8 Your answer is 2 5/8.
