If XY=18, YZ=14, and XZ=20, find the radius of each circle.

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

8 0

Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.

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NNADVOKAT [17]

Answer: The value of x =2 units.

Explanation:

Since we have given that

AD= CD

BE= EA

So, we get that D and E are the mid-points of AC and AB respectively.

So, by Mid- point theorem , which states that the line joining the two midpoints is parallel to third side and it is half in length of third side i.e.

$DE=\frac{1}{2}BC$