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2 years ago

What is the height of the area is 21 the first base is two in the second base is five

Mathematics

1 answer:

Ivanshal [37]2 years ago

4 0

To find the area of a rectangle multiply its height by its width. For a square you only need to find the length of one of the sides (as each side is the same length) and then multiply this by itself to find the area.

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Help asap help please.

Xelga [282]

Answer:

30(x+1)/(x+7)

Step-by-step explanation:

This is not a rational expression because denominator has a domain of which it can be undefined.

To rationalize multiply by the reciprocal of the denominator (1/6+1/x+1)

___5___ *(6)(x+1) --> _____30(x+1)_____ --> 30x+1_ --> 30x+1

1/6+1/x+1 *(6)(x+1)--> 6(x+1)/6 + 6(x+1)/(x+1) --> (x+1)+6 --> x+7

Final Answer: 30(x+1)/(x+7)

7 0

2 years ago

How many 2/5 are in 3/2

kari74 [83]

Answer:

3/2 / 2/5 = 3/2 x 5/2 = 15/4

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Please answer this question now in two minutes

shepuryov [24]

Answer:

40m Since it is the shortest side

Step-by-step explanation:

7 0

2 years ago

A survey of students' favorite sports was taken from a random sample of

White raven [17]

Answer:

129

Step-by-step explanation:

Considering the survey to be representative, you can simply multiply the share of students p preferring “Track & Field” with the whole school population at the same time to estimate the number of such students in the whole school.

First we need to find the relative share p of such answers in the study by dividing it by the sum of answers, assuming that the table is complete for that random sample:

p = 4/(8 + 5 + 4) = 4/17

Then for the whole school we get 550 p ≈ 129.4

6 0

2 years ago

HELP with these questions

zlopas [31]

Step-by-step explanation:

transform the parent graph of f(x) = ln x into f(x) = - ln (x - 4) by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

0 = ln (x - 4)

$e^{0} = e^{ln (x - 4)}$

1 = x - 4

+4 +4

5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

$\frac{0}{-1} = \frac{-ln (x - 4)}{-1}$

1 = ln (x - 4)

$e^{1} = e^{ln (x - 4)}$

e = x - 4

+4 +4

e + 4 = x

6.72 = x

(6.72, 1)

Domain: x - 4 > 0

+4 +4

x > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ into f(x) = - 3ˣ⁺⁵ by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0. the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

= - 3⁰⁺⁵

= - 3⁵

= -243

Horizontal Asymptote: y = 0 (explanation above)

5 0

3 years ago