<h2>Frequency of allele </h2>
Explanation:
Hardy Weinberg Equilibrium is used to calculate the allelic as well as genotypic frequency
Allelic frequency of dominant and recessive allele is represented by p and q respectively whereas genotypic frequency of dominant genotype is represented by 
and 
respectively
Given:
H allele (p) = hairy heffalump (dominant)
h allele (q) = hairless heffalump (recessive)
36% of heffalump population is hairless represents the % of recessive genotype, hh () =36%
Calculation of frequency of the h allele (q) :
Frequency of genotype hh () will be: 36/100=0.36 or 0.6*0.6
Frequency of h allele (q) will be 0.6
Answer: I believe you need to examine the layers, the color, texture.
Answer:
Four.
Explanation:
Initially four haploid spores are produced by meiosis. We know that during meiosis pairing between homologous chromosomes occurs and this created genetic difference between the divided cells. Exchange of genetic material doesn't occur during mitosis so mitotically divided cells are similar. Thus when spores divide by mitosis and become eight in number, here will be no new genetic difference.
The complete sentence will be -
A nucleus within an ascus undergoes meiosis, producing four haploid spores, which then undergo mitosis, producing eight haploid ascospores. These haploid ascospores contain a maximum of four different genetic types.
Answer:
ATP.
Explanation:
Glycolysis may be defined as the process by which breakdown of glucose molecule occurs into the form of ATP. Glycolysis can occur in the presence as well as in the absence of oxygen.
The initial step of the glycolysis is the formation of glucose-6-phosphate from the glucose molecule. The ATP starts this process of the glucose oxidation with the help of the enzyme hexokinase. The first step of the glucose oxidation is the energy driven process that requires the ATP molecule.
Thus, the correct answer is option (4).
Answer:
All other things being equal the size of a population will decrease if the death rates exceeds the birthrates...
