3 years ago

Solve the equation. 6x=2x^2+1

1 answer:

7 0

6x = 2x^2 + 1
2x^2 - 6x + 1 = 0
$x= \frac{-(-6) \pm \sqrt{(-6)^2-(4 \times 2 \times 1)}}{2 \times 2}\\=\frac{6\pm\sqrt{36-8}}{4}\\=\frac{6\pm\sqrt{28}}{4}\\=\frac{6\pm2\sqrt{7}}{4}\\=\frac{3\pm\sqrt{7}}{2}\\=\frac{3+\sqrt{7}}{2}\,or\,\frac{3-\sqrt{7}}{2}$

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erastovalidia [21]

All you need is the double angle identity:

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nataly862011 [7]

5x(8 - 4)/4 - 2

Remember to follow PEMDAS.

First, subtract 8 and 4

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Next, follow the left -> right rule, and multiply 5x and 4

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Divide by 4

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Finally, note that one has a variable, and the other has a constant, and so you cannot combine.

5x - 2 is your answer

hope this helps

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