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Mashcka [7]
3 years ago
6

Please help, my computer is about to die and this is due in a few minutes. Will mark brainlist if correct

Mathematics
1 answer:
SpyIntel [72]3 years ago
5 0

Answer:

x = 1.5

Step-by-step explanation:

Based in the tangent-secant theorem,

KI*JI = HI²

KI = (x + 0.5)

JI = 0.5

HI = 1

Plug in the values

(x + 0.5)(0.5) = 1²

0.5x + 0.25 = 1

0.5x = 1 - 0.25

0.5x = 0.75

x = 0.75/0.5

x = 1.5

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tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

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And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

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Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

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g1 = 2.0ms^-2 and  

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Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

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Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

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Answer:

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Step-by-step explanation:

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