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forsale [732]
3 years ago
5

∫ ex (sec x + tan²x) dx = ? a) eˣsec²x b) eˣsecx c) eˣtan²x d) eˣtanx

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0

None of these options seem to be correct. You can check each result by differentiation:

(e^x\sec^2x)'=e^x(\sec^2x+2\sec^2\tan x)=e^x\sec^2x(1+\tan x)

(e^x\sec x)'=e^x(\sec x+\sec x\tan x)=e^x\sec x(1+\tan x)

(e^x\tan^2x)'=e^x(\tan^2x+2\tan x\sec^2x)=e^x\tan x(\tan x+2\sec^2x)

(e^x\tan x)'=e^x(\tan x+\sec^2x)

But none of these are equivalent to e^x(\sec x+\tan^2x)...

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Juan wishes to build a garden at the bottom of his property. He wants to split it in two, like the diagram below, so he can plan
SCORPION-xisa [38]

Answer:

20 ft by 60 ft

Step-by-step explanation:

"What should the dimensions of the garden be to maximize this area?"

If y is the length of the garden, parallel to the stream, and x is the width of the garden, then the amount of fencing is:

120 = 3x + y

And the area is:

A = xy

Use substitution:

A = x (120 − 3x)

A = -3x² + 120x

This is a downward facing parabola.  The maximum is at the vertex, which we can find using x = -b/(2a).

x = -120 / (2 · -3)

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When x = 20, y = 60.  So the garden should be 20 ft by 60 ft.

4 0
3 years ago
Triangle HIJ is similar to triangle KLM. Find the measure of side MK. Round your answer to the nearest tenth.
AnnZ [28]

Answer:

MK\approx 87.7

Step-by-step explanation:

By definition, similar polygons have corresponding sides in a constant proportion. Therefore, we can set up the following proportion (ratio of corresponding sides) to solve for MK:

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andreyandreev [35.5K]

Answer:

37.5 cm

Step-by-step explanation:

See attached for reference.

let the diagonal be x,

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AnnZ [28]
Make image more close pls.Then I will answer
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