Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
156 feet larger
Step-by-step explanation:
Alright so 160% of 10 is 16 , now we do 16x16 = 256
Now we do 10x10 to find the old square feet which is 100
256-100=156
Answer:
y=5/2
Step-by-step explanation:
I think it’s either 4 or 20
5 x 4 =20
6 x 4 =20
Answer:
It's $32.39.
Step-by-step explanation:
35.99 - 35.99*10% =
=35.99 - 35.99*0.1
=35.99 - 3.599
=32.391
32.391 is close to 32.39 so we will round it to that number.
The answer is $32.39.
