<em><u>Answer:</u></em>
<em><u>O</u></em><em><u>P</u></em><em><u>T</u></em><em><u>I</u></em><em><u>O</u></em><em><u>N</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>I</u></em><em><u>S</u></em><em><u> </u></em><em><u>R</u></em><em><u>I</u></em><em><u>G</u></em><em><u>H</u></em><em><u>T</u></em><em><u>.</u></em>
<em><u>7j+14k=28</u></em><em><u> </u></em><em><u> </u></em><em><u>A</u></em><em><u>N</u></em><em><u>D</u></em><em><u> </u></em><em><u>J</u></em><em><u>=</u></em><em><u>2</u></em>
<em><u>T</u></em><em><u>H</u></em><em><u>E</u></em><em><u>R</u></em><em><u>E</u></em><em><u>F</u></em><em><u>O</u></em><em><u>R</u></em><em><u>E</u></em><em><u>,</u></em><em><u>7</u></em><em><u>*</u></em><em><u>2</u></em><em><u>+</u></em><em><u>1</u></em><em><u>4</u></em><em><u>K</u></em><em><u>=</u></em><em><u>2</u></em><em><u>8</u></em>
<em><u>1</u></em><em><u>4</u></em><em><u>+</u></em><em><u>1</u></em><em><u>4</u></em><em><u>K</u></em><em><u>=</u></em><em><u>2</u></em><em><u>8</u></em>
<em><u>1</u></em><em><u>4</u></em><em><u>K</u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em>
<em><u>K</u></em><em><u>=</u></em><em><u>1</u></em>
<em><u /></em>
Answer:
- x = 0, mult: 3
- x = -4, mult: 2
- x = -5, mult: 2
Step-by-step explanation:
When a polynomial is shown in factored form, its zeros are the values of x that make the factors zero.
The factor x is zero when x=0.
The factor (x+4) is zero when x=-4.
The factor (x+5) is zero when x=-5.
__
The multiplicity of a zero is the number of times a given factor is a factor of the polynomial. It is the exponent of the factor.
x = 0 has multiplicity 3.
x = -4 has multiplicity 2.
x = -5 has multiplicity 2.
P = 6s
s = 3.4
P = 6(3.4) = 20.4 cm
Answer:
25
Step-by-step explanation:
so 9.9 ounce bag of takis
9.9/0.396=25
Answer:
Step-by-step explanation:
We assume that there are 100 sour candies, Thus-
26 % of candy are grape implies that 26% of 100 candies are grape that is equal to 26
Now remaing candies that are not grape are 100-26 = 74
Based on the rule of multiplication:
P(A ∩ B) = P(A)/ P(B|A)
In the beginning, there are 26grape candies, probability of choosing first grape candy = 26C1 = 26
After the first selection, we replace the selected grape candy so there are still 100 candies in the bag P(B|A) = 100C3 = 100 x 99 x 98 x 97!/3! X 97!
= 50 x 33 x 98
So probability =1/ 50 x 33 x 98 x 26
= 1/4204200