Round 9.39 to the nearest whole number.

A bag contains 9 red marbles, 18 orange marbles, 2 yellow marbles, and 5 purple marbles. A marble is drawn at random from the ba

vlada-n [284]

Answer:

8/17

Step-by-step explanation:

total balls= 9 + 18 + 2 + 5 = 34

balls drawn should NOT be Orange.

so, 34 - 18 (as there are 18 orange balls)

16 balls

probability= 16/34 = 8/17

answer = 8/17

7 0

3 years ago

A family drove 165 miles in 3 hours. At the same rate, how many miles could they travel in 8 hours

Oksi-84 [34.3K]

First you have to divide 165 by 3, which is 55. and then 55 multiplied by 8 is 440. so in 8 hours, they could travel 440 miles.

6 0

3 years ago

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A culture started with 5000 bacteria after 5 hours it grew to 6500 bacteria predict how many bacteria will be present after 16 h

postnew [5]

Answer:

After 16 hours bacterial count will be 11600.

Step-by-step explanation:

Bacterial growth is always an exponential growth in a given culture.So the formula for the growth will be

Final counts of bacteria = Initial counts × $(rate of growth)^{time}$

Given from first part Initial counts = 5000

Final counts= 6500 and time of growth = 5 hours

Then we will get the value of rate of growth of bacteria from the bacteria

⇒ 6500 = 5000× $(rate)^{5}$

$(rate)^{5}= \frac{6500}{5000} = 1.3$

$Rate = \sqrt[5]{1.3} = 1.05$

Now again to get the value of bacteria after 16 hours

Final Count = 5000× $(1.05)^{16}$

= 5000×2.32

= 11600

7 0

3 years ago

Help please this should be turn in 5mijs please

True [87]

The answer is c) F and H

7 0

3 years ago

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The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e. $\mu=61$ and $\sigma=9$

To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and $34+3(9)$ .

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ . (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0

2 years ago