Solve for X please help

The least total cost method (LTC) lot-sizing technique calculates the order quantity by comparing the carrying cost and the setu

rewona [7]

Answer:

True

Step-by-step explanation:

The least total cost method is the method in which the total cost of the ordering cost and the total carrying cost is equal among various lot size available.

The order quantity should be choose when the total ordering cost and the total carrying cost equal to each other

The formula to compute the economic order quantity is shown below:

a. The computation of the economic order quantity is shown below:

$= \sqrt{\frac{2\times \text{Annual demand}\times \text{Ordering cost}}{\text{Carrying cost}}}$

It is always be expressed in units

The formula to compute the ordering cost is

$= \frac{Annual\ demand}{Economic\ order\ quantity}\times ordering\ cost\ per\ order$

And, the formula to compute the carrying cost is

$= \frac{Economic\ order\ quanity}{2}\times carrying\ cost\ per\ unit$

Hence, the given statement is true

8 0

2 years ago

Determine each of the following.

castortr0y [4]

Answer:

(a) $\{1,2,3,4,5,6,7,8,9,10\}$

(b) 10

(c) $\{\}$

(d) 0

(e) 1024

Step-by-step explanation:

(a)

A = {x ∈ Z | 0 < x, x² ≤ 100}

We need to find all the elements of given set.

The given conditions are

$0$ ... (1)

$x^2\leq 100$

Taking square root on both sides.

$-\sqrt{100}\leq x\leq \sqrt{100}$

$-10\leq x\leq 10$ .... (2)

Using (1) and (2) we get

$0$

Since x ∈ Z,

$A=\{1,2,3,4,5,6,7,8,9,10\}$

(b)

We need to find the value of | {x ∈ Z | 0 < x, x² ≤ 100}| or |A|. It means have to find the number of elements in set A.

$|A|=10$

| {x ∈ Z | 0 < x, x² ≤ 100}| = 10

(c)

B = {x ∈ Z | x > 10, x² ≤ 100}

We need to find all the elements of given set.

The given conditions are

$x>10$ ... (3)

$x^2\leq 100$

It means

$-10\leq x\leq 10$ .... (4)

Inequality (3) and (4) have no common solution, so B is null set or empty set.

$B=\{\}$

(d)

We need to find the value of |{x ∈ Z | x > 10, x² ≤ 100}| or |B|. It means have to find the number of elements in set B.

$|B|=0$

|{x ∈ Z | x > 10, x² ≤ 100}| = 0

(e)

We need to find the value of | P(A) |. P(A) is the power set of set A.

Number of elements of a power set is

$N=2^n$

where, n is the number of elements of set A.

We know that the number of elements of set is 10. So the value of |P(A)| is

$|P(A)|=2^{10}$

$|P(A)|=1024$

Therefore |P(A)|=1024.

7 0

2 years ago

How many megabytes of data can a 4.7 gigabyte dvd store?

dedylja [7]

The answer is 4700 megabytes.

1 giga = 1000 mega

1 gigabyte = 1000 megabyte
4.7 gigabyte = x megabyte

1 gb : 1000 mb = 4.7 gb : x
x = 1000 mb * 4.7 gb : 1 gb
x = 4700 mb

3 0

2 years ago

By using the table in the handbook, the present value of $12,000 for six years compounded at 6 percent semiannually is

denis23 [38]

Take a look at the attachment to see the solution.
A = future value
P = principal (P = 12,000)
r = interest rate (r=6)
n = time periods (n=12)