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tino4ka555 [31]
1 year ago
12

A person crosses a 600m long street in 5 minutes what is his speed in kilometre per hour.

Mathematics
1 answer:
bekas [8.4K]1 year ago
8 0

This is an exercise in kinematics, on Uniform Rectilinear Motion.

To start solving this exercise, we obtain the data:

Distance (d) = 600 m

Time (T) = 5 minutes = 300 sec

Speed (V) = ?

<em>Since it asks us for the speed in </em><em>kilometers per hour (Km/h)</em><em>, we perform a time conversion, from minutes to seconds. Taking into account that </em><em>1 minute = 60 seconds.</em>

<h3>5 minutes * (60 sec/1 minutes) = 300 sec</h3>

To calculate the speed we apply the following formula:

<h3> V = D/T</h3>

We substitute our data in the given formula and solve:

<h3>V = 600 m / 300 sec</h3>

V = 2 m/s

<em>But since it asks us for the speed in km/h, we carry out a conversion, taking into account that </em><em>1 km = 1000 meters</em><em> and </em><em>3600 seconds = 1 hour</em><em>, so:</em>

<h3>2 m/s * (1 km/1000 m)*(3600 s/1 hr) = 7.20 km/h</h3>

Answer: <u><em>The speed of the person is 7.20 km/h.</em></u>

<u><em /></u>

<h2>Skandar</h2>
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Steps/Reasons/Explanation:

Question: Solve for b. -9 b = 27. b = ?

<u>Step 1</u>: Divide both sides by -9.

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<u>Step 2</u>: Simplify \frac{27}{9} to 3.

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Two kinds of crated cargo, A and B, are to be shipped by truck. Each crate of cargo A is 50 cubic feet in volume and weighs 200
BlackZzzverrR [31]

Answer:

The correct answer is option b)

50a+10b<1000; 200a+360b < 7200; a> 0; b>0

Step-by-step explanation:

We are given that Two kind of crated cargo namely A and B to be shipped by truck.

<u>Cargo A:</u>

Volume of each crate of cargo A = 50 cubic ft

Weight of each crate of cargo A = 200 pounds

Let number of crates of cargo A to be shipped = a

Total volume of 'a' crates of cargo A = 50a cubic ft

Total weight of 'a' crates of cargo A = 200a pounds

<u>Cargo B:</u>

Volume of each crate of cargo B = 10 cubic ft

Weight of each crate of cargo B = 360 pounds

Let number of crates of cargo B to be shipped = b

Total volume of 'b' crates of cargo B = 10b cubic ft

Total weight of 'b' crates of cargo B = 360b

Total volume allowed in the truck is 1000 cubic ft

Total volume of 'a' crates of Cargo A and Total volume of 'b' crates of Cargo B = 50a+10b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

50a+10b ....... (1)

Total weight allowed (load limit) in the truck is 7200 pounds

Total weight of 'a' crates of Cargo A and Total weight of 'b' crates of Cargo B = 200a+360b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

200a+360b ....... (1)

And number of crates of cargo A and B are always a positive number.

So, a > 0 and b > 0.

So, the correct answer is option b.

<em>b. 50a+10b<1000; 200a+360b < 7200; a> 0; b>0</em>

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