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tino4ka555 [31]
1 year ago
12

A person crosses a 600m long street in 5 minutes what is his speed in kilometre per hour.

Mathematics
1 answer:
bekas [8.4K]1 year ago
8 0

This is an exercise in kinematics, on Uniform Rectilinear Motion.

To start solving this exercise, we obtain the data:

Distance (d) = 600 m

Time (T) = 5 minutes = 300 sec

Speed (V) = ?

<em>Since it asks us for the speed in </em><em>kilometers per hour (Km/h)</em><em>, we perform a time conversion, from minutes to seconds. Taking into account that </em><em>1 minute = 60 seconds.</em>

<h3>5 minutes * (60 sec/1 minutes) = 300 sec</h3>

To calculate the speed we apply the following formula:

<h3> V = D/T</h3>

We substitute our data in the given formula and solve:

<h3>V = 600 m / 300 sec</h3>

V = 2 m/s

<em>But since it asks us for the speed in km/h, we carry out a conversion, taking into account that </em><em>1 km = 1000 meters</em><em> and </em><em>3600 seconds = 1 hour</em><em>, so:</em>

<h3>2 m/s * (1 km/1000 m)*(3600 s/1 hr) = 7.20 km/h</h3>

Answer: <u><em>The speed of the person is 7.20 km/h.</em></u>

<u><em /></u>

<h2>Skandar</h2>
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Answer:

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For the interpretation we consider a value for d small is is between 0-0.2, medium if is between 0.2-0.8 and large if is higher than 0.8.

And on this case 1.713>0.8 so we have a large effect size

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Step-by-step explanation:

Previous concepts

The Effect size is a "quantitative measure of the magnitude of the experimenter effect. "

The Cohen's d effect size is given by  the following formula:

d = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1 +s^2_2}{2}}}

Solution to the problem

And for this case we can assume:

\bar X_1 =78.24 the mean for females

\bar X_2 =66.25 the mean for males

s_1 = s_2= 7 represent the deviations for both groups

And if we replace we got:

d = \frac{78.24 -66.25}{\sqrt{\frac{7^2 +7^2}{2}}}= 1.713

For the interpretation we consider a value for d small is is between 0-0.2, medium if is between 0.2-0.8 and large if is higher than 0.8.

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This value of d=1.713 are telling to us that the two groups differ by 1.713 standard deviation and we will have a significant difference between the two means.

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Here x_1=m, y_1=n, x_2=h, y_2=0

              $=\left( \frac{m+h}{2}, \frac{n+0}{2}\right  )

$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right  )

<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here x_1=0, y_1=0, x_2=x,  y_2=y

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$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{x}{2}, \frac{y}{2}\right  )

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Multiply by 2 on both sides of the equation, we get

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Multiply by 2 on both sides of the equation, we get

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