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tino4ka555 [31]
1 year ago
12

A person crosses a 600m long street in 5 minutes what is his speed in kilometre per hour.

Mathematics
1 answer:
bekas [8.4K]1 year ago
8 0

This is an exercise in kinematics, on Uniform Rectilinear Motion.

To start solving this exercise, we obtain the data:

Distance (d) = 600 m

Time (T) = 5 minutes = 300 sec

Speed (V) = ?

<em>Since it asks us for the speed in </em><em>kilometers per hour (Km/h)</em><em>, we perform a time conversion, from minutes to seconds. Taking into account that </em><em>1 minute = 60 seconds.</em>

<h3>5 minutes * (60 sec/1 minutes) = 300 sec</h3>

To calculate the speed we apply the following formula:

<h3> V = D/T</h3>

We substitute our data in the given formula and solve:

<h3>V = 600 m / 300 sec</h3>

V = 2 m/s

<em>But since it asks us for the speed in km/h, we carry out a conversion, taking into account that </em><em>1 km = 1000 meters</em><em> and </em><em>3600 seconds = 1 hour</em><em>, so:</em>

<h3>2 m/s * (1 km/1000 m)*(3600 s/1 hr) = 7.20 km/h</h3>

Answer: <u><em>The speed of the person is 7.20 km/h.</em></u>

<u><em /></u>

<h2>Skandar</h2>
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3 years ago
2-4/5 x 1/2 = ________ *simplify answer*
Slav-nsk [51]
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3 0
3 years ago
Jim places ​$10,000 in a bank account that pays 9.8​% compounded continuously. After 2 ​years, will he have enough money to buy
OLga [1]

Answer:

9.8% compounded continuously is a better deal

Step-by-step explanation:

Given that Jim wants to buy a car which costs 12160 after 2 years.

He has two options before him,

i) 9.8% compounded continuously

ii) 10% compounded semiannually

Principal he has is 10000 dollars

Hence we have

Value after 2 years for option i) = 10000e^{0.098(2)} \\=12165.27

(after rounding off to two decimals)

Option ii)

For compounding continuously for 4 half years we get

Final amount = 10000(1+\frac{10}{200} )^{4} \\=10000(1.05)^4\\= 12155.06

(after rounding off to two decimals)

Comparing we find sufficient cash is provided by option I

3 0
3 years ago
Find the centroid of the thin plate bounded by the graphs of the functions g(x )= x^2 (x - 1) + 2 and f(x) = x^2 + 2 with delta
lawyer [7]

Answer:

X = 6/5

Y = 176/56

Step-by-step explanation:

Given

g(x) = x²(x-1)+2

f(x) =x²+2

We find the limits as follows:  x²(x-1)+2 = x²+2

⇒ x²(x - 1 - 1) = x²(x - 2) = 0

⇒  x₁ = 0  and x₂ = 2

If x = 1

g(1) = (1)²(1 - 1) + 2 = 2

f(x) = (1)² + 2 = 3

then

f(x) > g(x)

We get the Area

A = ∫(f(x)- g(x))dx =∫((x²+2)-( x²(x-1)+2))dx =  ∫x²(2-x)dx = (2/3)x³-(1/4)x⁴+C

A = (16/3) - 4 = 4/3

X = (1/A)∫(x(f(x)- g(x)))dx = (3/4)∫(x³(2-x))dx = (3/4) ((1/2)x⁴-(1/5)x⁵)+C

X = (3/4) ((1/2)(2)⁴-(1/5)(2)⁵) = (3/4)(8-32/5) = (3/4)(8/5) = 6/5

Y = (1/(2A))∫((f(x))²-(g(x))²)dx = (3/8)∫((x²+2)²-( x²(x-1)+2)²)dx

Y = (3/8)∫(-x⁶+2x⁵-4x³+8x²)dx = (3/8)(-(1/7)x⁷+(1/3)x⁶-x⁴+(8/3)x³+C)

Y = (3/8)(-(1/7)(2)⁷+(1/3)(2)⁶-(2)⁴+(8/3)(2)³) = (3/8)(176/21) = 176/56

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3 years ago
Solve for c. 60 = 4c
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Answer:

60 = 4c     | :4

15 = c


4 0
3 years ago
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