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AfilCa [17]
3 years ago
15

Please can someone answer

Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer: 10 cm

Step-by-step explanation:

The answer would be 10cm for the boys because if you think about it all together for boys and girls it’s 161 cm and girls have 151 cm so if you add them toge your suppose to get 161 cm so the answer is 10 cm

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Elsa's fish tank has 19 liters of water in it. She plans to add 4 liters per minute until the tank has more than 47 liters. What
kozerog [31]

Leila's fish tank has 18 liters of water in it. She plans to add 5 liters per minute until the tank has more than 58 liters. What are the possible numbers of minutes Leila could add water? Use t for the number of minutes.

Write your answer as an inequality solved for t.

 

58<18+5t

40<5t

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7 0
3 years ago
Look at the table. Make a conjecture about the sum of the first 25 positive even numbers.
insens350 [35]
Even number are of the form 2n.  The sum of this sequence is the average of the first and last terms times the number of terms.

So the first term is 2 and the 25th term is 50 so the sum is:

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52*12.5=650

The conjecture they wish you to make is that for n terms, the sum will be:

s=n(n+1)

And for 25 terms that would give you:

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6 0
4 years ago
Read 2 more answers
Simplify the expression:<br> 7r2+5r2+9r
jenyasd209 [6]

Answer:

9r+7r+9r

Step-by-step explanation:

4 0
3 years ago
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PLEASE HELP ASAP! I WILL GIVE BRAINLIEST!
olga_2 [115]
In 75 minutes you travelled 30 kilometers, so the rate is 30/75=0.4km/minute

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6 0
3 years ago
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A waffle cone has a volume of 31.254 cubic centimeters and a radius of
arlik [135]

Answer:

4.78 cm

Step-by-step explanation:

The formula for the volume of a cone of radius r and height h is

V = (1/3)πr²h.  Here, V = 31.254 cm³ and r = 2.5 cm.  

We begin by solving V = (1/3)πr²h for the unknown height, h:

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h = ------------------------  =  --------------------------  =  --------------------  ≈  4.78 cm

            (1/3)πr²                       π(2.5 cm)²               19.635 cm²

5 0
3 years ago
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