The solution to the problem is as follows:
The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know}
let f(x)=9x +13 and g(x)=2x+4
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f'(x)=9 and g'(x)=2 </span>
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therefore just substitute the equations in. </span>
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y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2))
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Answer:
Second option
Step-by-step explanation:
They have two congruent pairs of sides and one congruent pair of angles.
Answer:
-13a^2 + 170ab - 13b^2.
Step-by-step explanation:
1. 36(a+b)^2 - 49(a-b)^2
This is the difference of 2 squares: a^2 - b^2 = (a + b)(a - b).
36(a+b)^2 - 49(a-b)^2
= (6(a + b) + 7(a - b))( 6(a + b) - 7(a - b))
= (6a + 7a + 6b - 7b)( 6a - 7a + 6b + 7b)
= (13a - b)(-a + 13b)
If you require the expansion of this it is:
-13a^2 + 170ab - 13b^2.
Answer:
3
Step-by-step explanation:
x+10=13
x+10-10=13-10
Simplfiy
x=3
The function d(t) represents the distance traveled by the train after t hours. d(5) is the total distance traveled by the train after 5 hours, which means 6:00 pm. The d(2) is the total distance traveled by the train after two hours, 3:00 pm. The expression d(5) - d(2) represents the total distance traveled by the train from 3:00 pm to 6:00 pm or for traveling at a constant speed for 3 hours.
