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Annette [7]
2 years ago
13

Show 3.5, 0 0n quadrant plane

Mathematics
1 answer:
Fiesta28 [93]2 years ago
8 0

Answer:

Right 3.5 units

Step-by-step explanation:

Well, the coordinates go (x,y) so just plug it in..

(3.5, 0)

Go across (to the right) 3.5 and up 0, that's it.

Hope this helps :)

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The Wagner family uses up a 1/2-gallon jug of milk every 3 days. At what rate do they drink milk?
luda_lava [24]

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\frac{1}{6} gallon per day

Step-by-step explanation:

Rate = gallons per day

Rate = \frac{0.5 gallons}{3 days} = \frac{1 gallon}{6 days}

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If 54 oranges cost N36. Find the costs of 3 oranges
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4.5

Step-by-step explanation:

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Which drawing shows two lines that intersect at Point a ax, tab, two lines ab, straight x a.​
leonid [27]

The drawing which shows two lines that intersect at Point, A is as represented in Choice 1: Top-left corner.

Discussion:

In geometry, a line or straight line was introduced by ancient mathematicians to represent straight objects with negligible width and depth.

  • Lines are therefore an idealization of such objects, which are often described in terms of two points or referred to using a single letter.

Ultimately, The drawing which shows two lines that intersect at Point, A are as represented in Choice 1: Top-left corner.

Read more on intersection of lines:

brainly.com/question/9047265

5 0
2 years ago
This is for geometry and I need help...
Elina [12.6K]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Suppose we write the numbers $1,2,3,4,5,6$, and then color each number red or blue. The coloring is called factorific if there i
Oxana [17]

Answer:

The probability that his coloring is factorific is 0.28125

Step-by-step explanation:

For calculate the probability is necessary to identify the total number of ways to color the six number. This can be calculate with the rule of multiplication as:

2*2*2*2*2*2=64

Because we have 2 options to color every number.

For know the number of ways in which the coloring is factorific, first we need to identify the divisors of each number:

1: the divisor is 1

2: The divisors are 2 and 1

3: The divisors are 3 and 1

4: The divisors are 4, 2 and 1

5: The divisors are 5 and 1

6: The divisors are 6, 3 and 1

From these information we analyse that for made a factorific coloring, is necessary that the number 1 is color blue. Additionally if the number 4 is color blue, the number 2 needs to be color blue and if the number 6 is blue, the number 3 needs to be blue.

So, the number of ways in which we can create a factorfic number is determined by the following cases:

  • The number 2 is blue and the number 3 is blue: In this case we have 1 option for number 1, one for number 2 and 1 for number 3. Taking into account that the number 2 and 3 are blue, if the number 4 and 6 are blue or red doesn't change the fact that the coloring is going to be factorific. So, we have two options for number 3 and 2 options for number 6. Finally the color of the number 5 is independent of the colors of number 2 and 3, so we also have 2 options for coloring number 5 and the coloring is going to be factorific. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    2          </u>=   8

number 1    number 2    number 3   number 4  number 5  number 6

At the same way we can calculate the following cases:

  • The number 2 is blue and the number 3 is red:  If the number 3 is red, the coloring is only going to be factorific is number 6 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    1          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is red:  If the number 2 and 3  are red, the coloring is only going to be factorific is number 4 and 6 are red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>           1   </u>  *<u>         2    </u>* <u>    1          </u>=  2

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is blue:  If the number 2 is red, the coloring is only going to be factorific is number 4 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          1   </u>  *<u>         2    </u>* <u>    2          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

If we sum all the cases, we obtain 18 ways to make a factorific coloring. So the probability can be calculated as:

P= \frac{18}{64} =  0.28125

4 0
3 years ago
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