Question

Wyatt is going to a carnival that has games and rides. Each game costs $1. 25 and each ride costs $2. 75. Wyatt spent $20. 25 altogether at the carnival and the number of rides he went on is twice the number of games he played. Determine the number of games Wyatt played and the number of rides Wyatt went on.

Answer 1

In the carnival the number of games number of rides Wyatt went on is 3 and 6 respectively.

What is system of equation?

A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.

The number of unknown objects can be find using the system of solution.

Given information-

The cost of each game is $1.25.

The cost of each ride is $2.75.

Total amount of money spent by the Wyatt is $20.25.

The number of rides he went on is twice the number of games he played.

Suppose the number of games Wyatt played is x and the number of rides he went in the carnival is y.

As, the number of rides he went on is twice the number of games he played. Thus,

$y=2x$

Let the above equation as equation one.

As total amount of money spent by the Wyatt is $20.25 and The cost of each game is $1.25 and the cost of each ride is $2.75. Thus,

$1.25x+2.75y=20.25$

Put the value of y in the above equation from the equation one as,

$1.25x+2.75(2x)=20.25\\1.25x+5.5x=20.25\\6.75x=20.25\\x=3$

Thus the number of games he played is 3.

Put this value of x in the equation one as,

$y=2\times3\\y=6$

Thus the number rides Wyatt went on is 6.

Hence, In the carnival the number of games number of rides, Wyatt went on is 3 and 6 respectively.

Learn more about the system of equations here;

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