What is the solution for the equation -3d/d^2-2d-8 + 3/d-4 = -2/d+2
1 answer:
-3d/(d^2-2d-8) + 3/(d-4) = -2/(d+2)
factor
-3d/(d-4) (d+2) +3/(d-4) = -2/(d+2)
multiply by (d-4)(d+2) on each side
(d-4)(d+2)[-3d/(d-4) (d+2) +3/(d-4)] = (-2/(d+2))*(d-4)(d+2)
distribute
-3d +3(d+2) = -2(d-4)
distribute
-3d +3d+6 = -2d+8
combine like terms
6 = -2d+8
subtract 8 to each side
-2 = -2d
divide by -2
1 =d
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