We can rewrite the expression under the radical as
then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that
since both 
and 
return the same number , and 
captures both possibilities. From here, we have
The absolute values disappear on all but the 
term because all of 
, 
and 
are positive, while 
could potentially be negative. So we end up with
Answer:
F= 3x^2
Step-by-step explanation:
1) Multiplying exponents causes them to add, for instance if you were to multiply x^3 * x^4 the final product would be x^7. If you were to divide exponents then they would subtract.
2) Similarly in this problem you would determine the missing factor by dividing the product from -10x^3
3) Using the steps above, begin dividing.
-30x^5 / -10x^3
4) -30 divided by -10 is 3 and as mentioned in step number one, you subtract exponents whenever they are divided by each other. 5-3=2
5) Due to all of the steps mentioned above, The answer is 3x^2
Answer:
there are forty odd numbers
Step-by-step explanation:
