Just do how many minutes are in a hour and do that for 2days but 24 times two
<span>Amoeba splits 3 times an hour. If Amoeba can split into two every 20 mins then if you divide 60 mins (which would be an hour) by 20 mins (the time they split) you would find that Amoeba can split 3 times in an hour. The question asks how many times it can split in two hours. To find this you have to multiply the 3 times 2. This means that a single Amoeba can split 6 times in two hours. There are 15 Amoeba which means if you take 15 Amoeba time 6 in two hours and 90 would be your answer. There will be 90 Amoeba after the two hours.</span>
1430000 is the answer to Converting 1.43 g/mL to the unit g/m3 Also, <span>1 ml = 1cm3 = 1E-6 m3 </span>
1.43/ml= 1.43E-6 g/m3 (1.43 x 10-6 g/m3) and 1.43 x 106 (grams / cubic meter) =0.15158 kg / m<span>3</span>
Answer:
2.48 kg
Step-by-step explanation:
1 - ⅗ = ⅖
⅖ × 6.2 = 2.48
Answer:
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

The proportion of infants with birth weights between 125 oz and 140 oz is
This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So
X = 140



has a pvalue of 0.9772
X = 125



has a pvalue of 0.8413
0.9772 - 0.8413 = 0.1359
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.